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N76 [4]
3 years ago
10

In a class of 30 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose

to raise his or her hand. Eight hands go up. Then the professor asked everyone with a pierced ear to do likewise. This time there are 25 hands raised. How many students have piercings both on their ears and their noses?
Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0
There are 4 students who have piercings both on their ear and their noses.

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Uh where's problem??

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3 years ago
Identify what Number property is shown for each statement
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i think answer are big enough

8 0
3 years ago
Factors of x3 – 9x2 + 5x – 45 by grouping
kati45 [8]
Important:  Use the symbol "^" to denote exponentiation:

<span>x3 – 9x2 + 5x – 45        NO
</span><span>x^3 – 9x^2 + 5x – 45    YES

Look at the first 2 terms.  They can be rewritten as x^2(x-9).  Then look at the last 2 terms.  They can be rewritten as 5(x-9).  So, x-9 is the common factor here.   Thus, the original expression becomes:

(x^2-5)(x-9).

Note that x^2-5 can be factored, so that the final 3 factors are:

(x-sqrt(5)), (x+sqrt(5)), (x-9).</span>
8 0
3 years ago
Test the claim that the proportion of people who own cats is larger than 40% at the 0.025 significance level. The null and alter
Alecsey [184]

Answer:

H 0 : p ≤ 0.4 H a : p > 0.4

And based on the alternative hypothesis we can conclude that we have a right tailed test

Step-by-step explanation:

Data given

n=300 represent the random sample size

\hat p=0.45 estimated proportion of people with cats

p_o=0.40 is the value that we want to test

\alpha=0.025 represent the significance level

z would represent the statistic

p_v represent the p value

Null and alternative hypothesis

We want to test if the true proportion of people with cats is higher than 0.4, so then the best alternative is:  

Null hypothesis:p\leq 0.4  

Alternative hypothesis:p > 0.4  

H 0 : p ≤ 0.4 H a : p > 0.4

And based on the alternative hypothesis we can conclude that we have a right tailed test

The statistic is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.45 -0.4}{\sqrt{\frac{0.4(1-0.4)}{300}}}=1.768  

5 0
3 years ago
Raymond walked 3/4 of a mile last weekend. This weekend he walked 1/2 as far. How far did Raymond walk this weekend?
ololo11 [35]
He walked 3/8 of a mile this weekend. You multiply the numerator in 3/4 by the numerator in one half, and get a numerator of 3. You multiply the denominator of 3/4 by the denominator of 1/2, and get a denominator of 8
8 0
4 years ago
Read 2 more answers
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