Answer:
 Na⁺
Explanation:
In the given atom: 
   Number of protons  = 11 
   Number of neutrons  = 12 
 
So, the number of electrons  = 10
The number of protons within an atom is used to determine the kind of atom we have been given. 
Since the number of protons is the same as the atomic number, here the atomic number is 11 and this is Sodium .
  In this sodium atom, the number of protons is more than the number of electrons; 
  Charge = number of protons  - number of electrons  = 11 - 10  = +1 
So, we have a Na⁺
 
        
             
        
        
        
Part 1)
Answer:
Explanation:
As we know by equation of charging of the capacitor we will have

so we will have

here we know that


so we have

Part b)
Answer:
The time will increase.
Explanation:
As we know that on increasing the value of the resistance the the product of the resistance and capacitance will increase so the time will increase to get the above voltage.
Part c)
Answer:
The capacitor discharges through a very low resistance (the lamp filled with ionized gas), and so the discharge time constant is very short. Thus the flash is very brief.
Explanation:
Since the lamp resistance is very small so the energy across the lamp will totally lost in very short interval of time
Part d)
Answer:
Once the lamp has flashed, the stored energy in the capacitor is gone, and there is no source of charge to maintain the lamp current. The lamp "goes out", the lamp resistance increases, and the capacitor starts to recharge. It charges again and the process will repeat.
Explanation:
Since we know that the battery is connected to the given system so after whole energy of capacitor is flashed out it is again charged by the battery and the process will continue
 
        
             
        
        
        
Can you write out the question please? :) Sorry, i don't see it on the paper
 
        
             
        
        
        
Answer: Hmm... Ok lets see here 1st one would be Diffraction, 2nd one would be Refraction, and the 3rd would be Reflection, and the 4rth one should be Reflection as Well :D
Explanation: Hole This Helps :)
 
        
                    
             
        
        
        
Answer:
Given:
v1=32m/s,
v2=35m/s,
d1=250m,
d2=?
If both cars are travelling in the same direction, one at 32ms-1 and the other at 35 ms-1 then their relative velocity is Vr 3ms-1(by vector addition).
The time to catching Jim is t=d1/Vr= 250/3 = 83.3s
The distance traveled by the patrol car travel before catching Jim is d2 = v2t = v2 d1/Vr =35∙250/3= 2916.7m 
Answer: d2= 2916.7m
Explanation: