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3 years ago

Explain how the atmosphere and hydrosphere interact to create weather

Physics

1 answer:

ELEN [110]3 years ago

3 0

Answer:

The interaction between the atmosphere and hydrosphere usually consist of the water cycle.

Explanation:

The atmosphere and the hydrosphere interact to create weather activity by the change of states of water, which is usually known as the Water Cycle.

The sun that heats the water from the hydrosphere produces the water evaporation, forming water vapor into the atmosphere. This water vapor is then cooled and condensed into the atmosphere to form liquid water, that is released to the hydrosphere as precipitation in form of rain or snow, to star over the cycle.

I hope it helps you!

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A series of processes on Earth’s surface and in the crust and mantle that slowly change rocks from one kind to another is called

amid [387]

A series of processes on Earth's surface and in the crust and in the mantle that slowly change rocks from one kind to another is called the rock cycle. This cycle is a group of changes. We all know that the rock has 3 kinds which are igneous rocks, the sedimentary rocks, and the metamorphic rocks. The igneous rocks in the rock cycle can change to the sedimentary rocks or to the metamorphic rocks. The sedimentary rocks can also change to the igneous rocks or to the metamorphic rocks. The metamorphic rocks can change to the igneous rocks or to the sedimentary rocks. All depends on the process it undergoes and the factors present to affect the change it undergoes.

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3 years ago

A 55 kg cheerleader uses an oil-filled hydraulic lift to hold four 110 kg football players at a height of 1.0 m. If her piston i

AVprozaik [17]

Answer:

$D = 55.2 cm$

Explanation:

As we know that the total mass of the all four players is given as

$M = 4\times 110$

$M = 440 kg$

diameter of the piston of cheer leader is given as

$d_1 = 16 cm$

are of cross-section is given as

$A_1 = \pi r^2$

$A_1 = \pi(0.08)^2 = 0.02 m^2$

mass of the cheer leader is given as

m = 55 kg

so the pressure due to cheer leader is given as

$P_{in} = \frac{mg}{A_1}$

$P_{in} = \frac{55 \times 9.81}{0.02}$

$P_{in} = 26835 Pa$

Now on the other side pressure must be same

so we have

$\frac{Mg}{A} + \rho gH = P_{in}$

$\frac{440 \times 9.8}{A} + (900)(9.8)(1) = 26835$

$A = 0.24 m^2$

$\pi r^2 = 0.24$

$r = 0.276 m$

so diameter on the other side is given as

$D = 2 r$

$D = 55.2 cm$

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3 years ago

What is atom and what are its particles

beks73 [17]

Answer:

An atom is a smallest particle of an element.

Explanation:

It's particles are proton , electron and neutron.

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3 years ago

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Which of these is an experiment generally regarded as being first carried out by James Joule?

Sholpan [36]

1. The correct answer among the choices provided is the third option. Measuring the temperature increase of water from doing work by stirring it is an experiment generally regarded as being first carried out by James Joule.
2. Joule's experiment directly shows that heat is a form of energy. He wanted to make a different way of measuring energy.

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3 years ago

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A solid circular plate has a mass of 0.25 kg and a radius of 0.30 m. It starts rolling from rest at the top of a hill 10 m long

KATRIN_1 [288]

To solve the problem it is necessary to apply the equations related to the conservation of both kinetic of rolling objects and potential energy and the moment of inertia.

The net height from the point where it begins to roll with an inclination of 30 degrees would be

$h=Lsin30$

$h=10sin30$

$h=5m$

In the case of Inertia would be given by

$I = \frac{mR^2}{2}$

In general, given an object of mass m, an effective radius k can be defined for an axis through its center of mass, with such a value that its moment of inertia is

$I = mk^2$