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Serga [27]
3 years ago
8

Explain how the atmosphere and hydrosphere interact to create weather

Physics
1 answer:
ELEN [110]3 years ago
3 0

Answer:

The interaction between the atmosphere and hydrosphere usually consist of the water cycle.      

Explanation:

The atmosphere and the hydrosphere interact to create weather activity by the change of states of water, which is usually known as the Water Cycle.

<u>The sun that heats the water from the hydrosphere produces the</u> water evaporation,<u> forming water vapor into the atmosphere</u>. <u>This water vapor is then cooled and</u> <u>condensed </u><u>into the atmosphere</u> to form liquid water, <u>that is released to the hydrosphere as</u> precipitation in form of rain or snow, to star over the cycle.            

I hope it helps you!

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A physics student throws a softball straight up into the air. The ball was in the air for a total of 3.56 s before it was caught
meriva

Answer:

The initial velocity of the softball is 14.711 meters per second.

Explanation:

This is a case of an object which experiments a free fall, that is, an uniform accelerated motion due to gravity and in which effects from air friction and Earth's rotation can be neglected.

From statement we must understand that the student threw the softball upwards and it is caught at original position 3.56 seconds later. Initial and final heights, time and gravitational acceleration are known and initial speed is unknown. The following equation of motion is used:

y = y_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g \cdot t^{2} (Eq. 1)

Where:

y_{o} - Initial height of the softball, measured in meters.

y - Final height of the softball, measured in meters.

v_{o} - Initial velocity of the softball, measured in meters per second.

t - Time, measured in seconds.

g - Gravitational acceleration, measured in meters per square second.

If we know that y = y_{o}, t = 3.56\,s and g = -9.807\,\frac{m}{s^{2}}, the initial velocity of the softball is:

v_{o}\cdot (3\,s)+\frac{1}{2}\cdot (-9.807\,\frac{m}{s^{2}} )\cdot (3\,s)^{2} = 0

3\cdot v_{o} -44.132\,m= 0

v_{o} = 14.711\,\frac{m}{s}

The initial velocity of the softball is 14.711 meters per second.

8 0
3 years ago
a current of 180 mini amphere passes through a conductor for 5minute calculate the quantity of electricity transported​
oksano4ka [1.4K]

Answer:

Explanation:

You can calculate the total electric charge that passes through the conductor as q=It=(180\times 10^{-3})(5\times 60)= 54 C. It means that the number of electron that passes through the conductor is:

n=\frac{q}{e}=\frac{54}{1.6\times 10^{-19}}=33.75\times 10^{19}

8 0
2 years ago
África tiene más de 1000 lenguas, pero solo 50 son habladas por más de 500 mil personas, explica si esto es un aspecto positivo
Misha Larkins [42]

Answer:

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7 0
3 years ago
Which is an example of gaining a static charge by conduction?
lianna [129]

Answer:

shuffling shoes

Explanation:

7 0
3 years ago
The nucleus of most atoms is composed of which of the following sub-atomic particles?
Blababa [14]

Answer:

protons (+ charge) & neutrons (neutral charge)

however protons has a positive charge so it determined what atom it is.

7 0
3 years ago
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