$100x should be greater than or equal to $2500. X being the number of computers sold. If you divide 100 by 2500 you will know how many computers he need to sell.
$100x >(or equal to) $2500
Answer:
x = 14.6
ZA = 30.8
ZB = 33.2
Step-by-step explanation:
First, solve x: (knowing all angles of a triangle are 180º)
116º + (2x + 4)º + (3x-13)º = 180º
116 + 2x + 4 + 3x - 13 = 180
2x + 3x = 180 + 13 - 4 - 116
5x = 73
x = 73/5 = 14.6
ZA = 3*14.6 - 13 = 30.8
ZB = 2*14.6 + 4 =33.2
Test:
116º + 33.2º + 30.8º = 180º
Answer:
the 1st graph that has a point of (4,5)
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.
Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.
An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.
Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.
Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.
Part C:
Given that </span><span>Natalie
can only attend a school in her designated zone and that Natalie's zone is
defined by y < −2x + 2.
To identify the schools that
Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.
For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true
For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true
For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false
For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true
For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false
For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false
Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>
Answer:
¼ box
Step-by-step explanation:
Ezra sold ⅓ box of tangerines.
Anthony sold ¾ as many as Ezra = ¾ × ⅓ box
Cancel the 3s = ¼ × ¹/₁ box
Multiply numerators and denominators = ¼ box
Anthony sold ¼ box of tangerines.
