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yKpoI14uk [10]
3 years ago
6

9x^2(y^5)/3xy^7 simplify

Mathematics
1 answer:
Ghella [55]3 years ago
6 0

Answer:

( 9x^2y^5 /3  x)(y^7)

=3x^3y^12

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Como puedo resolver esta factorización? Factoriza la siguiente expresión sacando el factor común a) 15x2y − 25xy2 + 75x2y2 Ayúde
Karo-lina-s [1.5K]

Answer:

5xy (3x - 5y + 15xy)

Step-by-step explanation:

Ahora, si quiero tomar factores comunes, debo buscar algo que divida todos los términos de la expresión.

Este término que va a dividir todos los términos de la expresión es 5xy

Por lo tanto, para factorizar 15x2y - 25xy2 + 75x2y2

Tengo;

5xy (3x - 5y + 15xy)

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What expression is equivalent to 2(24x-18), 3(16x-12), 4(12x-9)
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a(b-c) = ab - ac

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All of the expressions are equivalent to 48x - 36.
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Which expression is equivalent to the following complex fraction?
iVinArrow [24]

Answer:

Option B

Step-by-step explanation:

Numerator:

\dfrac{3}{x -1 }-4 =\dfrac{3}{x-1}-\dfrac{4*(x-1)}{x-1}\\\\

                 =\dfrac{3- 4x -4*(-1)}{x-1}=\dfrac{3-4x+4}{x-1}\\\\\\=\dfrac{-4x+7}{x-1} \:  \textbf{ [Combine like terms]}

Denominator:

2-\dfrac{2}{x-1}=\dfrac{2*(x-1)}{x-1}-\dfrac{2}{x-1}\\

                = \bf \dfrac{2x-2-2}{x-1}\\\\\\= \dfrac{2x-4}{x-1}\\\\= \dfrac{2*(x- 2)}{x-1}

\dfrac{\dfrac{3}{x-1}-4}{2-\dfrac{2}{x-1}}=\dfrac{\dfrac{-4x+7}{x-1}}{\dfrac{2*(x-2)}{x-1}}

                 \bf = \dfrac{-4x+7}{x-1}*\dfrac{x-1}{2(x-2)} \ \ \  \textbf{ [(x-1) in the numerator and denominator will be cancelled]}\\\\\\=\dfrac{-4x+7}{2(x-2)}

6 0
3 years ago
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