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3 years ago

Let f(x)=(x+4)^2−3.

1 answer:

4 0

A is the answer.
it's translated up by 9 units b/c |-3| + 6 = 9.
if it were a translation 9 units to the right, the function would be y=(x-9)^2 (starting from the origin)

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Find the area of triangle ABC. The figure is not drawn to scale.

balu736 [363]

Sin(63)=x/7
0.89100652418= x/7 > 0.89100652418 (7) = x/7(7)
6.23704566932=x This is the height
the area of a triangle is A=BH/2 or Base * Height /2
A= (6.23704566932)(8)/2
A=24.9481826773 or 24.95 cm^2

6 0

3 years ago

Sixty percent of the students at a certain school wear neither a ring nor a necklace. Twenty percent wear a ring and 30 percent

Reptile [31]

Answer:

0.4

Step-by-step explanation:

Given

60 % wear neither ring nor a necklace

20 % wear a ring

30 % wear necklace

This question can be Solved by using Venn diagram

If one person is choosen randomly among the given student the probability that this student is wearing a ring or necklace is

$P\left ( wear \ ring\ or \ necklace )+P\left ( neither\ ring\ or\ necklace)=1$

$P\left ( wear \ ring\ or\ necklace )=1-0.6=0.4$

The sum of probabilty is equal to 1 because it completes the set

Therefore the required probabilty is 0.4

7 0

3 years ago

Prove that if sin (2 + y) = 3 sin (x - y), then tan x = 2 tany.

nignag [31]

Answer:

The proof is given below.

Step-by-step explanation:

Given: ( the correct question and ans is as follow )

sin (x + y) = 3sin ( x - y)

To Prove

tan x = 2 tan y

Proof:

$\sin (x+y) = 3\sin (x-y)$

Using the identities

$\sin (A+B) = \sin A.\cos B + \cos A.\sin B\\and\\\sin (A-B) = \sin A.\cos B - \cos A.\sin B\\$

we get

$\sin x.\cos y + \cos x.\sin y = 3(\sin x.\cos y - \cos x.\sin y)\\\sin x.\cos y + \cos x.\sin y = 3\sin x.\cos y - 3\cos x.\sin y$

Now we will take sin x . cos y to the left hand side and cos x . sin y to the right hand side,we get

$3\sin x.\cos y - \sin x.\cos y = 3\cos x.\sin y +\cos x.\sin y\\2\sin x.\cos y =4\cos x.\sin y\\\sin x.\cos y =2\cos x.\sin y \ \textrm{4 divide by 2}\\ \frac{\sin x}{\cos x} =2\times \frac{\sin y}{\cos y} \\\textrm{we know identity }\\\frac{\sin x}{\cos x} = \tan x\\\frac{\sin y}{\cos y} = \tan y\\\therefore \tan x = 2\tan y\ ...............{PROVED}$

7 0

3 years ago

X= Enter the number that belongs in the green box.

Marat540 [252]

72 degrees

When the transversal cuts through, the angles are now the same (I forgot the term).

<h3>I am pretty sure this is the answer! Correct me if I'm wrong!!</h3>

8 0

2 years ago

If f(x)=3x+1 and g(x)=x^2-6 find (f-g)(x)

8090 [49]

Hi there!

• f(x) = 3x + 1
• g(x) = x² - 6

Then,
According to th' question :-

(f - g)(x) = f(x) - g(x)

= 3x + 1 - (x² - 6)

= 3x + 1 - x² + 6

= -x² + 3x + 7

Hence,
Option 2ⁿᵈ : -x² + 3x + 7 is Correct.

~ Hope it helps!

6 0

3 years ago

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