Answer:
square pyramid...........
We use the fact that if x+y+z = 0, then x³+y³+ z³ = 3 x y z.<span>
(x</span>²-y²) + (y²-z²) + (z²-x²) = 0<span>
also: (x-y) + (y-z)+ (z-x) = 0
we assume that: x </span>≠y ≠ z.
<span>
hence,
(x²-y²)³ + (y²-z²)³ + (z²-x²)³ ÷ (x-y)³ + (y-z)³ + (z-x)³
= 3 (x</span>²-y²) (y²-z²) (z²-x²) ÷ [3 (x-y) (y-z) (z-x)]
<span>= (x+y) (y+z) (z+x)</span>
The y-axis is behaving like a mirror in the graph.
If you stand at where ABCD is and a mirror is placed along the y-axis, your image will be at where A'B'C'D' is.
Therefore this is a reflection in the y-axis or in the line

For reflection in the y-axis, we negate the x-coordinates.
The rule for this reflection in the y-axis is
It is matter
Happy to help!
(Mark brainliest)