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vovikov84 [41]
3 years ago
11

A decrease of one unit in the ph scale above represents a tenfold increase in the hydrogen ion concentration of a solution. for

example, a solution having a ph of 4 is 10 times more acidic than a solution with a ph of 5. if acid precipitation rain changes the ph of a pond from 7.5 to 6.5, the level of hydrogen ion has changed by a factor of ________.
Chemistry
1 answer:
Bond [772]3 years ago
7 0
Answer is: 10.
pH₁ (pond) = 7,5. Pond is bacic.
pH₂ (pond) = 6,5. Pond is acidic.
c₁( H₃O⁺) = ? concentration of hydronium ion.
c₂ (H₃O⁺) = ?
pH = -log c(H₃O⁺) ⇒ c(H₃O⁺) = 10∧(-pH).
c₁(H₃O⁺) = 10⁻⁷·⁵ = 3,2·10⁻⁸ M(mol/dm³).
c₂(H₃O⁺) = 10⁻⁶·⁵ = 3,2·10⁻⁷ M(mol/dm³).
factor = c₂(H₃O⁺)/ c₁(H₃O⁺) = 3,2·10⁻⁷/3,2·10⁻⁸ = 10 (ten times greater concentration).

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if it takes 54 mL of 0.1 NaOH to neutralize 125 mL of an HCL solution, what is the concentration of HCL?
alexira [117]

Answer:

0.0432 M

Explanation:

We are given;

Volume of NaOH as 54 mL

Molarity of NaOH as 0.1 M

Volume of HCl as 125 mL

We are required to determine the concentration of HCl

Step 1; We write a balanced equation for the reaction between NaOH and HCl

The balanced equation is given by;

NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)

Step 2: Determine the number of moles of NaOH

Moles = Volume × molarity

Therefore;

Moles of NaOH = 0.054 L × 0.1 M

                          = 0.0054 Moles

Step 3: We use the mole ratio to determine the moles of HCl

From the equation;

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = Moles of HCl

Thus; moles of HCl = 0.0054 moles

Step 4: Determine the concentration of HCl

We know that;

Molarity = Moles ÷ Volume

Therefore;

Molarity of HCl = 0.0054 moles ÷ 0.125 L

                         = 0.0432 M

Therefore, the concentration of HCl is 0.0432 M

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Answer:

A substance that is dissolved in a solution is called a solute

Explanation:

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