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horsena [70]
3 years ago
5

A substance that is dissolved in a solution is called a(n) __________________.

Chemistry
2 answers:
Fudgin [204]3 years ago
8 0

Answer:

A substance that is dissolved in a solution is called a solute

Explanation:

Solute is the substance which is dissolved

Solvent is where you dissolve the solute (usually liquids)

Solution = Solute + solvent

Natalka [10]3 years ago
3 0

Answer: solute

Explanation: Imagine dissolving a cube of sugar in a glass of water, the cube of sugar is the solute while water is the solvent.

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How many moles of sulfuric acid (H2SO4) are present in 500.0 mL of 0.15 M H2SO4 solution?
galben [10]

Answer:

Number of moles = 0.075 mol

Explanation:

Volume = 500.0 mL = 0.5 (Converting to L by dividing by 1000)

Molarity = 0.15 M

Number of moles = ?

The relationship between the quantities is given as;

Molarity  = Number of moles / Volume

Number of moles = Molarity * Volume

Number of moles = 0.15  * 0.5

Number of moles = 0.075 mol

7 0
3 years ago
The Following questions pertain to a 2.2M solution of hydrocyanic acid at 25°C. pKa = 9.21 at 25°C. Find the concentrations of a
horsena [70]
1) Chemical reaction: HCN + H₂O → CN⁻ + H₃O⁺.
c(HCN) = 2,2 M = 2,2 mol/L.
pKa(HCN) = 9,21.
Ka = 6,16·10⁻¹⁰.
[CN⁻] = [H₃O⁺] = x.
[HCN<span>] = 2,2 M - x.
</span>Ka = [CN⁻] · [H₃O⁺] / [HCN].
6,16·10⁻¹⁰ = x² / 2,2 M -x.
Solve quadratic equation: [CN⁻] = [H₃O⁺] = 0,0000346 M.
[HCN] = 2,2 M - 0,0000346 M = 2,199 M.

2) pH = - log[H₃O⁺].
pH = -log( 0,0000346 M).
pH = 4,46.
Hydrocyanic acid and hydronium ion (H₃O⁺) are acids. Cyanide anion (CN⁻) is the strongest base in the system, cyanide anion accept protons in chemical reaction.
pKb = pKw - pKa.
pKb = 14 - 9,21 = 4,79.

6 0
3 years ago
Write A balanced equation showing the formation of copper (II) nitrite from its elements
34kurt

Answer:

Cu(s) + N₂(g) + 2O₂(g) ⟶ Cu(NO₂)₂(s)

4 0
4 years ago
What volume of methane gas at 237 K and 101.33 kPa do you have when the volume is decreased to 0.50 L, with a temperature of 300
Alexxandr [17]

Answer: A volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.

Explanation:

Given: T_{1} = 237 K,   P_{1} = 101.33 kPa,      V_{1} = ?

T_{2} = 300 K,      P_{2} = 151.99 kPa,        V_{2} = 0.50 L

Formula used is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{101.33 kPa \times V_{1}}{237 K} = \frac{151.99 kPa \times 0.50 L}{300 K}\\V_{1} = 0.592 L

Thus, we can conclude that a volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.

8 0
3 years ago
The measured quantity 0.00410 g written in scientific notation is _______. Using prefixes, the number can be written as ________
vovangra [49]

Answer:

4.10x10⁻³g.

4.10 mg.

Explanation:

Hello,

In this case, considering the given number, we can see it has two digits after the first nonzero digit that is four (4) which is also at the third decimal place, it means that the scientific notation has a negative power as it is at the left of the given zeros, therefore it is:

4.10x10⁻³g.

Moreover, since the proper prefix for the factor x10⁻³ is milli, the number with prefix is:

4.10 mg.

Best regards.

6 0
3 years ago
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