$\bf \textit{sum of all interior angles of a polygon}\\\\
180(n-2)\quad 
\begin{cases}
n=\textit{number of sides}\\
---------\\
n=10
\end{cases}\implies 180(10-2)\implies 1440\\\\
-------------------------------\\\\
\begin{array}{lclll}
&x + 5\\&x + 10\\&x + 20\\&x + 30\\&x + 35\\&x + 40\\&x + 60\\&x + 70\\&x + 80\\+&x + 90\\
&----\\
&10x+440
\end{array}\implies 
\begin{array}{llll}
10x+440=1440
\\\\\\
10x=1000
\\\\\\
x=\cfrac{1000}{10}\implies x=100
\end{array}$

so.. to get every angle, simply plug in 10 for "x" for each.

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