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finlep [7]
4 years ago
13

Josh has a toy car of mass 3 kg tied to a string of length 2 m. He ties the string to a pole and has the toy car drive in a circ

le around the pole at a speed of 3 m/s. a) what is the centripetal force
Physics
1 answer:
GalinKa [24]4 years ago
3 0

When anything moves in a circle, the centripetal force
acting on it is

               Force  =  (mass) x (centripetal acceleration)

                          =   (mass) x (speed² / radius of the circle) .

So          Force = (3 kg) x (3 m/s)² / (2 m)

                         = (3 kg) x (9 m²/s²) / (2 m)

                         =  (27 kg-m²/s²) / (2 m)

                         =    13.5  kg-m/s²    =    13.5 Newtons 
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Object A with a mass of 500 kilograms hits stationary object B with a mass of 920 kilograms. If the collision is elastic, what h
Vika [28.1K]
In elastic collision, both the kinetic energy and momentum are conserved. Conservation means that both the kinetic energy and momentum will have the same values before and after elastic collision.

<span>As the object A has low mass than object B. Hence upon collision, object B moves forward, while object A will move backward. So option "C" is correct. </span>

5 0
4 years ago
What is a overly-simplified definition of Einstein's theory of general relativity?​
Phoenix [80]

Answer:

the laws of physics are the same for all non-accelerating observers

Explanation:

6 0
3 years ago
If a box is pushed across a floor with a force of 130N. The frictional force acting between the box and the floor is 30N, over a
Sidana [21]
The force acting in the front direction is the 130N.
The frictional force is acting backwards          30N.

1) The net force is 130N - 30N    =  100N

2)  s  = ut + (1/2)at^2             u = 0,  Start from rest,  s = 25m t =5.

25 = 0*5  +  (1/2)* a * 5^2.

25 = 0  +  25/2  * a.

25  =    (25/2)a.      Divide 25 from both sides.

1 =  (1/2)* a.          Cross multiply.

2 = a.

a = 2 m/s^2.

3) Mass of the box
Net Force,  F = ma
                   100 =  m*2.        Divide both sides by 2.
                    
                     100/2  =  m
                       50       =  m.
                        m  = 50 kg.

4)  Final velocity ,   v = u + at.
                                   v  =  0  + 2*5 = 10 m/s.
                                  
   Kinetic Energy,  K  =  (1/2) * mv^2.
                                    =    1/2  * 50 * 10 * 10.
                                    =      2500 J.
3 0
3 years ago
A man holds a child on his shoulders while watching a football match. How many work has he done if the game lasts for 2 hours? ​
Shalnov [3]

very interesting and amazing question u had asked but i get it...

Answer

  • work done is given by

W = Force × Displacement

  • but in above case force is exerted on the men as the weight of the child × gravitational pull of earth (9.8 m/s^2) but the displacement or movement is ZERO
  • there for W= F×0 =0
  • so even after carrying child for 2 hours work done by the men will be zero

<u>More</u><u> </u><u>examples</u>

  • a person standing straight and lifting weight
  • a person carry some weight and walk in a circular path and came back to its original position.........in this case also Displacement will be zero

------------------------------------

hope it helped u buddy

4 0
3 years ago
Read 2 more answers
If an 18-wheeler truck travels 280,000m to transport its cargo in 8 hrs. (28,800s). What was it’s average velocity?
hram777 [196]

Answer:

u can use a calculator to answer that question thats ur only hint

Explanation:

5 0
3 years ago
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