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Alisiya [41]
3 years ago
12

A ball is thrown straight upward with an initial velocity of 18.5m/s at the edge of a cliff that is 25.0m below the initial poin

t. What is the velocity of the ball at its maximum height?
Physics
1 answer:
kkurt [141]3 years ago
8 0

The velocity of the ball at its maximum height is zero (0).

The given parameters;

  • <em>initial vertical velocity of the ball, </em>v_y_0<em> = 18.5 m/s</em>
  • <em>height of the cliff, h = 25</em>

<em />

In a projectile motion, as the object ascends upwards, its vertical velocity decreases and eventually becomes zero as the object reaches maximum height.

This <em>velocity</em> starts to increase again as the object descends downwards and finally becomes maximum before the object hits the ground.

Thus, we can conclude that the velocity of the ball at its maximum height is zero (0).

Learn more here:brainly.com/question/10693605

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ira [324]

Answer:

B.

Explanation:

A beta particle is formed when a neutron changes into a proton and a high-energy electron. The proton stays in the nucleus but the electron leaves the atom as a beta particle.

6 0
3 years ago
A single strain gage has a nominal resistance of 120 ohm. For a quarter bridge with 120 ohm fixed resistors, strain gauge factor
natita [175]

Answer:

Output voltage is 1.507 mV

Solution:

As per the question:

Nominal resistance, R = 120\Omega

Fixed resistance, R = 120\Omega

Gauge Factor, G.F = 2.01

Supply Voltage, V_{s} = 3\ V

Strain, \epsilon = 1000\times 10^{-6}\ strain

Now,

To calculate the output voltage, V_{o}:

WE know that strain is given by:

\epsilon = \frac{(R + R')^{2}V_{o}}{RR'V_{s}\times G.F}

Thus

V_{o} = \frac{RR'V_{s}\epsilon \times G.F}{(R + R')^{2}}

Now, substituting the suitable values in the above eqn:

V_{o} = \frac{120\times 120\times 3\times 1000\times 10^{-6}\times 2.01}{(120 + 120)^{2}}

V_{o} = 1.507\ mV

6 0
4 years ago
A right triangle with the base labeled 40 meters and the height labeled 30 meters. The hypotenuse is a dotted arrow labeled R. W
Pepsi [2]

Answer:

The magnitude of the resultant vector R is 50 meters ⇒ 2nd answer

Explanation:

<u><em>The resultant vector</em></u> is the vector sum of two or more vectors

If the two vectors perpendicular to each other, then the magnitude of

the resultant vector is the square root of the sum of their squares

If x and y are two vectors perpendicular to each other, then the

magnitude of its resultant vector R is:

→ R=\sqrt{x^{2}+y^{2}}

Lets solve the problem

A right triangle with the base labeled 40 meters and the height labeled

30 meters

The hypotenuse is a dotted arrow labeled R

→ The base and the height of the right triangle are perpendicular

→ The hypotenuse is the resultant vector of them

Assume that x represents the base of the triangle and y represents the

height of it

By using the rule above

→ x = 40 m , y = 30 m

→ R=\sqrt{x^{2}+y^{2}}

→ R=\sqrt{(40)^{2}+(30)^{2}}

→ R=\sqrt{1600+900}

→ R=\sqrt{2500}=50

<em>The magnitude of the resultant vector R is 50 meters</em>

7 0
3 years ago
3. Which of the following is true about astronauts taking out the TRASH?
scoray [572]

Answer:

C

Explanation:

When trash accumulates, astronauts manually squeeze it into trash bags, temporarily storing almost two metric tons of it for relatively short durations, and then send it away in a departing commercial supply vehicle, which either returns it to Earth or incinerates it during reentry through the atmosphere.

6 0
3 years ago
A car speeds past a stationary police officer while traveling 135 km/h. the officer immediately begins pursuit at a constant acc
kykrilka [37]

(a) The time it takes for the police officer to catch up to the speeding car is determined as 0.31 s.

(b) The speed of the police officer  at the time he catches up to the driver is 136.8 km/h.

<h3>Time of motion of the police</h3>

The time taken for the police to catch up with the driver is calculated as follows;

v = at

where;

  • a is acceleration = 11.8 km/h/s, = 3.278 m/s²
  • v is velocity = 135 km/h = 37.5 m/s

t = v/a

t = 37.5/3.278

t = 11.4 seconds

(v1 - v2)t = ¹/₂at² --- (1)

(v1 - v2)t = v1²/2a --- (2)

From (1):

(v1 - 37.5)t = ¹/₂(3.278)t²

(v1 - 37.5)t = 1.639t²

v1 - 37.5 = 1.639t

v1 = 1.639t + 37.5  -----(3)

From (2):

(v1 - 37.5)t = v1²/(2 x 3.278)

(v1 - 37.5)t = 0.153 ----- (4)

solve 3 and 4;

(1.639t + 37.5 - 37.5)t = 0.153

1.639t² = 0.153

t² = 0.0933

t = 0.31 s

<h3>Speed of the police officer</h3>

v1 = 1.639(0.31) + 37.5 = 38 m/s = 136.8 km/h

Learn more about velocity here: brainly.com/question/4931057

#SPJ1

4 0
2 years ago
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