Question

A ball is thrown straight upward with an initial velocity of 18.5m/s at the edge of a cliff that is 25.0m below the initial point. What is the velocity of the ball at its maximum height?

Answer 1

The velocity of the ball at its maximum height is zero (0).

The given parameters;

• initial vertical velocity of the ball, $v_y_0$ = 18.5 m/s
• height of the cliff, h = 25

In a projectile motion, as the object ascends upwards, its vertical velocity decreases and eventually becomes zero as the object reaches maximum height.

This velocity starts to increase again as the object descends downwards and finally becomes maximum before the object hits the ground.

Thus, we can conclude that the velocity of the ball at its maximum height is zero (0).

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