A ball is thrown straight upward with an initial velocity of 18.5m/s at the edge of a cliff that is 25.0m below the initial poin
1 answer:
The velocity of the ball at its maximum height is zero (0).
The given parameters;
- <em>initial vertical velocity of the ball, </em>
<em> = 18.5 m/s</em>
- <em>height of the cliff, h = 25</em>
<em />
In a projectile motion, as the object ascends upwards, its vertical velocity decreases and eventually becomes zero as the object reaches maximum height.
This <em>velocity</em> starts to increase again as the object descends downwards and finally becomes maximum before the object hits the ground.
Thus, we can conclude that the velocity of the ball at its maximum height is zero (0).
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The magnitude of the force of friction is 40 N
Explanation:
To solve the problem, we just have to analyze the forces acting on the student and the scooter along the horizontal direction. We have:
- The constant pushing force forward, of magnitude F = 40 N
- The frictional force, acting backward,
Since the two forces are in opposite direction, the equation of motion is
where
m is the mass of the student+scooter
a is the acceleration
However, here the scooter is moving at constant speed: this means that its acceleration is zero, so
a = 0
And therefore,
which means that the magnitude of the force of friction is also equal to 40 N.
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