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Aliun [14]
3 years ago
7

A poll surveyed 503 video gamers, and 106 of them said they prefer playing games on a console rather than a computer. An executi

ve at a game console company claims that more than 25% of gamers prefer consoles. Does the poll provide convincing evidence that the claim is true? Use the level of significance.
Mathematics
1 answer:
Kitty [74]3 years ago
3 0

Answer:

The claim has no evidence to be supported.

On the contrary, there is enough evidence to support the claim that <em>less than 25% of gamers prefer consoles</em>.

Step-by-step explanation:

This is a hypothesis test for a proportion.

The sample has a size n=503.

The sample proportion is p=0.211.

p=X/n=106/503=0.211

The sample proportion is less than 25%, so we will test the claim that <em>less </em>than 25% of gamers prefer consoles.  

Then, the null and alternative hypothesis are:

H_0: \pi=0.25\\\\H_a:\pi

The significance level is assumed to be 0.05.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.25*0.75}{503}}\\\\\\ \sigma_p=\sqrt{0.000373}=0.019

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.211-0.25+0.5/503}{0.019}=\dfrac{-0.038}{0.019}=-1.9685

This test is a left-tailed test, so the P-value for this test is calculated as:

\text{P-value}=P(z

As the P-value (0.0245) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that less than 25% of gamers prefer consoles.

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Answer:

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Step-by-step explanation:

Given:

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Rewrite expression without the parentheses.

SOLUTION:

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Thus:

(b + 3) + 6 = b + 9

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The members of the basketball team ordered 5 tuna sandwiches at $3.99 each, 5 fish tacos at $2.75 each, 3 salads at $2.70 each,
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1/5x+y=2/5<br> 1/0x+1/3y=1/2
kkurt [141]
A) 
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<span>c) </span>
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<span>|4x - 3y = -5 </span>
<span>d) </span>
<span>|1/(x - 1) = y - 3 </span>
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<span>e) </span>
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4 0
3 years ago
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