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krok68 [10]
3 years ago
15

How long is each side of a square that has an area of 25 meters?

Mathematics
2 answers:
Sergio [31]3 years ago
4 0
The square root of 25 is 5, so each side is 5metres x
Rom4ik [11]3 years ago
4 0
A=s*s
25 = x \times x \\ 25 = {x}^{2}  \\  \sqrt{25}  =  \sqrt{ {x}^{2} }  \\ 5 = x
Each side is 5m
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6 0
3 years ago
- 6(x + 2) + 2x - 4 = 8(x - 2) + 8<br> does this have a solution if do why
kobusy [5.1K]

Answer:

Yes, there is a solution: - 2/3

Step-by-step explanation:

Step 1:

- 6 ( x + 2 ) + 2x - 4 = 8 ( x - 2 ) + 8

Step 2:

- 6x - 12 + 2x - 4 = 8x - 16 + 8

Step 3:

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Step 4:

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Step 5:

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Step 6:

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Answer:

- 2/3

Hope This Helps :)

6 0
3 years ago
Read 2 more answers
What is the factored form of the expression 5p^3-10p^2+3p-6
Ugo [173]

Answer: (5p^2+3)(p-2)

Step-by-step explanation:

In this problem, we need to write the factor form of expression .

5p^3-10p^2+3p-6

It can be done as follows :

5p^3-10p^2+3p-6=(5p^3+3p)+(-10p^2-6)

Taking common form the terms as follows :

=p(5p^2+3)-2(5p^2+3)

It can be also written as :

=(5p^2 +3)(p-2)

Hence, the factored form of  is

5 0
3 years ago
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Create your own unit rate example in which you have to determine the unit rate of two fractions with different units. Explain wh
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Manav can cover 1 mile of the distance in just 12 minutes.

<h3>How to calculate the unit rate?</h3>

The unit rate can be expressed in any unit for instance minute per mile, miles/hour, etc

if Manav covers 3 miles in 36 minutes, her unit rate in minutes per mile is expressed as:

Unit rate = 36min/3miles

Unit rate = 12 minutes/mile

Here,

This shows that Manav can cover 1 mile of the distance in just 12 minutes.

Learn more on unit rate here:

brainly.com/question/2375289

#SPJ1

8 0
2 years ago
If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
ozzi

<u>Answer:</u>

<em>Equation is  4x-6(6x-1) = -11 </em>

<u>Step-by-step explanation:</u>

<em>The set of equations given are                           </em>

<em>6x-y=1 </em>

<em>4x-3y=-11 </em>

A pair of linear equations in <em>two variables x and y is given</em> in the set of equations. If there are two variables we require two equations to find the <em>value of variables</em>. Substitution is one among the methods used to solve pair of linear equations in two variables.

Here we have to <em>determine the value of y</em> from the first equation and then substitute it in the second equation.

<em>6x-y=1 </em>

<em>y=6x-1 </em>

<em>Substituting this value in second equation 4x-6y=-11 </em>

<em>we get </em>

<em>4x-6(6x-1) = -11 </em>

7 0
3 years ago
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