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krok68 [10]
3 years ago
15

How long is each side of a square that has an area of 25 meters?

Mathematics
2 answers:
Sergio [31]3 years ago
4 0
The square root of 25 is 5, so each side is 5metres x
Rom4ik [11]3 years ago
4 0
A=s*s
25 = x \times x \\ 25 = {x}^{2}  \\  \sqrt{25}  =  \sqrt{ {x}^{2} }  \\ 5 = x
Each side is 5m
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Step-by-step explanation:

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Step-by-step explanation:

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Write the equation in standard form for the circle with center (-3,3) and radius 3
leva [86]

Answer:

(x+3)^2+(y−3)^2=9

Step-by-step explanation:

The equation for a circle is given by

(x−h)^2+(y−k)^2=r^2  where (h,k) is the center and r is the radius

(x− -3)^2+(y−3)^2=3^2

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3 0
3 years ago
Read 2 more answers
Solve for x rounded to the nearest hundredth: 10 - 3x = 5
igomit [66]

Answer:

x = 5/3

Step-by-step explanation:

You ALWAYS want your term to be by itself!! So what you need to do is move your constant away from it.

Step 1: Adjust as needed, subtract 10 from both sides of your equation. It should end up like this.

-3x = 5 - 10

Step 2: Solve as needed before continuing equation.

-3x = -5

Step 3: Now you need to get your term by itself. You should divide -3 on both sides of your equation so you should get something like this.

x = -5 / -3

Step 4: You're basically done now! Just simplify! NEGATIVES CROSS EACH OTHER OUT!!!

x = 5/3 OR 1.6

<em>KEY:</em>

<em>Negative and Negative = Positive</em>

<em>Negative and Positive = Negative</em>

<em>Positive and Positive = Positive</em>

4 0
3 years ago
Jerry solved the system of equations. x minus 3 y = 1. 7 x + 2 y = 7. As the first step, he decided to solve for y in the second
Reika [66]

Answer:

A. The variable x in the first equation has a coefficient of one so there will be fewer steps to the solution.

Step-by-step explanation:

Given

Equation\ 1: x - 3y = 1

Equation\ 2: 7x + 2y = 7

Required

Efficient way of solving the equations

<em>The efficient way of solving this problem is by solving for x in the first equation because it has a coefficient of 1;</em>

The evidence is shown as follows;

<em>Make x the subject of formula in equation 1</em>

x = 1 + 3y

<em>Substitute 1 + 3y for x in equation 2</em>

7x + 2y = 7

7(1 + 3y) + 2y = 7

<em>Open bracket</em>

7 + 21y + 2y = 7

7 + 23y =7

<em>Make y the subject of formula</em>

23y = 7 - 7

23y = 0

<em>Divide both sides by 23</em>

\frac{23y}{23} = \frac{0}{23}

y = 0

Recall that x = 1 + 3y

<em>Substitute 0 for y in the above expression</em>

x = 1 + 3(0)

x = 1 + 0

x = 1

Solving for y in the second equation will take more steps

6 0
3 years ago
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