25 tons equals how many pounds?

PLEASE SOMEONE DO THIS IM RUSHING SO BAD AND IM CRYING - GIVING BRAINLIEST!!!!!

LUCKY_DIMON [66]

Answer:

1.) $1.07

2.) $2.25

3.) $14.20

Step-by-step explanation:

1.) Toonie = 2 CAD

CAD = USD $1.57

$1.57 - $0.50 = $1.07 (USD)

2.) $2.75 - $5 = $2.25 (USD)

3.) $20 x 4 = 80

$80 - $65.80 = $14.20 (USD)

Hope this helped!

8 0

3 years ago

What is the slope of the graph shown below?

levacccp [35]

Answer:

2435

Step-by-step explanation:

6 0

3 years ago

A point has: no shape no color no size no physical characteristics all of the above

notka56 [123]

A point is an abstraction to point a location or vertex (intersection of lines). It has no size. Consequently it does not have shape or color or any physical characteristic.

Then the answer is all of the above.

7 0

3 years ago

Type the correct answer in each box. Use numerals instead of words. For this question, any answer that is not a whole number sho

egoroff_w [7]

Answer:

Step-by-step explanation:

Since we are not given the value of P, |Q|, R and S, we can as well assume values for them for the sake of this question.

Let P = 5, |Q| = 6, R =7 |S| = 2

Note that since Q and S are in modulus sign, they can return both positive and negative values.

P+Q = 5 + 6 (note that the positive value of Q is used since we need the greatest value of P+Q)

P+Q = 11

Hence the greatest value of P+Q is 11

For the least value of P+Q, we will use the negative value of Q as shown

P+Q = 5+(-6)

P+Q = 5-6

P+Q = -1

Hence the least value of P+Q is -1

Similarly:

R+S = 7 + 2 (note that the positive value of S is used since we need the greatest value of R+S)

R+S = 9

Hence the greatest value of R+S is 9

For the least value of R+S, we will use the negative value of S as shown

R+S = 5+(-2)

R+S = 5-3

R+S = 2

Hence the least value of P+Q is 2

NOTE THAT THIS ARE ASSUMED VALUES. ALL YOU NEED IS TO PLUG IN THE VALUES OF P, Q and R THAT YOU HAVE IN CASE THE VALUES DIFFERS.

5 0

3 years ago

A random sample of 121 automobiles traveling on an interstate showed an average speed of 73 mph. from past information, it is kn

tatiyna

121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range

$(73 - 2 \cdot 11, 73 + 2 \cdot 11) = (51,95)$

The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.

The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:

$\sigma = \dfrac{ 11}{\sqrt{121}} = 1$

So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range

$(73 - 2 \cdot 1, 73 + 2 \cdot 1) = (71,75)$

That's probably the answer they're looking for.

4 0

3 years ago