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nikitadnepr [17]
3 years ago
14

How do particles move in the different states of matter

Physics
1 answer:
sertanlavr [38]3 years ago
3 0
The particles in a solid are tightly packed and the particles do not move
The particles of liquid is less tightly packed and move with lesser kinetic energy than solids
The particles of gases are least tightly packed and the particles move around freely with the least kinetic energy than solids and liquids
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A(n) 6.6 kg bowling ball is rolling towards the bowling pins. If its momentum is 15.9 kg*m/s, how fast is it traveling, in m/s?
Vedmedyk [2.9K]

Answer:

2.4m/s towards the bowling pins

Explanation:

Given parameters:

Mass of the ball  = 6.6kg

Momentum of the ball  = 15.9kgm/s

Unknown:

Speed of the ball  = ?

Solution:

The momentum is the amount of motion a body posses;

      Momentum = mas x velocity

Insert the parameters and solve;

      15.9  = 6.6 x velocity

        velocity  = 2.4m/s towards the bowling pins

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An arthroscope can be inserted into a knee joint through a very tiny incision to help a doctor examine the knee. A light is tran
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Which color of the visible light spectrum has the most energy?
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B

Explanation:

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The radius of the aorta is «10 mm and the blood flowing through it has a speed of about 300 mm/s. A capillary has a radius of ab
stealth61 [152]

Answer:

(I). The effective cross sectional area of the capillaries is 0.188 m².

(II). The approximate number of capillaries is 3.74\times10^{9}

Explanation:

Given that,

Radius of aorta = 10 mm

Speed = 300 mm/s

Radius of capillary r=4\times10^{-3}\ mm

Speed of blood v=5\times10^{-4}\ m/s

(I). We need to calculate the effective cross sectional area of the capillaries

Using continuity equation

A_{1}v_{1}=A_{2}v_{2}

Where. v₁ = speed of blood in capillarity

A₂ = area of cross section of aorta

v₂ =speed of blood in aorta

Put the value into the formula

A_{1}=A_{2}\times\dfrac{v_{2}}{v_{1}}

A_{1}=\pi\times(10\times10^{-3})^2\times\dfrac{300\times10^{-3}}{5\times10^{-4}}

A_{1}=0.188\ m^2

(II). We need to calculate the approximate number of capillaries

Using formula of area of cross section

A_{1}=N\pi r_{c}^2

N=\dfrac{A_{1}}{\pi\times r_{c}^2}

Put the value into the formula

N=\dfrac{0.188}{\pi\times(4\times10^{-6})^2}

N=3.74\times10^{9}

Hence, (I). The effective cross sectional area of the capillaries is 0.188 m².

(II). The approximate number of capillaries is 3.74\times10^{9}

3 0
3 years ago
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