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Hunter-Best [27]
3 years ago
5

Clouds in space can begin as what​

Physics
1 answer:
asambeis [7]3 years ago
6 0

They begin as dark clouds and cosmic dust

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Need help with number <br> 50 <br> PLEASE HELP! Show all work please!
Pavel [41]

Answer:50 is b

Explanation:

v = 34757

6 0
3 years ago
Help!
muminat

Power P is the rate at which energy is generated or consumed and hence is measured in units that represent energy E per unit time t. This is:

P = E/t

Solving for t:

t = E/P

t = 6007 J / 500 W

t = 12.014 s

<h2>t ≅ 12 s</h2>

7 0
3 years ago
One type of slingshot can be made from a length of rope and a leather pocket for holding the stone. The stone can be thrown by w
grigory [225]

Answer:

15.66 rad/s

Explanation:

The vertical motion and horizontal motion are independent of each other.

t = √ ( 2 s/ g) where t = time for the ball to reach the ground and s is the height of the cliff = 18.0 m

t = √ ( 36 / 9.81 ) = 1.916 secs

horizontal distance travel = ut where u is the horizontal velocity of the stone = 30 × r (radius)

tangential velocity V = angular velocity ( ω) × radius

distance traveled = ω × r × t = 30 × r

radius cancelled on both side

ω = 30 / 1.9156 = 15.66 rad/s

4 0
3 years ago
Easy question. Answer should include one line reasoning
KATRIN_1 [288]
C.figure 3 is the answer had the same and got is right
7 0
3 years ago
Read 2 more answers
A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches
tiny-mole [99]

Answer:

26.8 seconds

Explanation:

To solve this problem we have to use 2 kinematics equations: *I can't use subscripts for some reason on here so I am going to use these variables:

v = final velocity

z = initial velocity

x = distance

t = time

a = acceleration

{v}^{2}  =  {z}^{2}  + 2ax

v = z + at

First let's find the final velocity the plane will have at the end of the runway using the first equation:

{v}^{2}  =  {0}^{2}  + 2(5)(1800)

v = 60 \sqrt{5}

Now we can plug this into the second equation to find t:

60 \sqrt{5}  = 0 + 5t

t = 12 \sqrt{5}

Then using 3 significant figures we round to 26.8 seconds

3 0
2 years ago
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