C.
Nitrogen has the atomic no. of 7 so the proton and the electron no. is 7.
Three more electrons are needed to fulfil the octet structure: 2,8
Electromagnetic waves can travel in vaccum but mechanical wave does not
Answer:
1.6 x 10^-5 T
Explanation:
i = 4 A
r = 0.05 m
The magnetic field due to long wire at a distance r is given by

B = 10^-7 x 2 x 4 / 0.05
B = 1.6 x 10^-5 T
Answer:
a =( -0.32 i ^ - 2,697 j ^) m/s²
Explanation:
This problem is an exercise of movement in two dimensions, the best way to solve it is to decompose the terms and work each axis independently.
Break down the speeds in two moments
initial
v₀ₓ = v₀ cos θ
v₀ₓ = 5.25 cos 35.5
v₀ₓ = 4.27 m / s
= v₀ sin θ
= 5.25 sin35.5
= 3.05 m / s
Final
vₓ = 6.03 cos (-56.7)
vₓ = 3.31 m / s
= v₀ sin θ
= 6.03 sin (-56.7)
= -5.04 m / s
Having the speeds and the time, we can use the definition of average acceleration that is the change of speed in the time order
a = (
- v₀) /t
aₓ = (3.31 -4.27)/3
aₓ = -0.32 m/s²
= (-5.04-3.05)/3
= -2.697 m/s²
Answer:
joules
joules
Explanation:
Let us convert the time in hours into seconds

Change in internal energy

where E is the internal energy in Joules
p is the power in watts
and t is the time in seconds

Joules
Amount of work done by the system

where P is the pressure and V is the volume
Substituting the given values in above equation, we get -

liter-atmospheres
Work done in Joules

Joules

Substituting the given values we get -

Thus
joules
joules