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My name is Ann [436]

3 years ago

6

Find a number that when subtracted from the numerator of 13/8 and added to the denominator of 13/8 results in fraction equivalen

t to 2/5

1 answer:

mariarad [96]3 years ago

3 0

The answer should be 6/15

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He answer is subjective probability. Subjective probability is when it has no prior calculations and the person is just guessing. Theoretical probability is when it’s based on prior calculations. Experimental probability is when you experiment and calculate.

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In 4 years time I saw me three times as old as Mary who is now nine years of age how old am I

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Find the solutions to the equation -5/2x+3/4x=-3\4

Usimov [2.4K]

Simplify both sides of the equation

-5/2 x +3/4 x = -3/4

Combine like terms

(-5/2 x + 3/4 x )

-7/4 x = -3/4

-7/4 x = -3/4

Multiply both sides by 4/(-7)

(4/-7)*(-7/4 x ) = (4/-7 ) * ( -3/4 )

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Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sampl

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Complete Question

Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sample of 15 students, the professors find the mean number of headaches is 19 and the standard deviation is 1.7. Assume the population distribution of number of headaches is normal.the correct conclusion at $\alpha =0.001$ is?

Answer:

There is no sufficient evidence to support the professor believe

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 18$

The sample size is $n = 15$

The sample mean is $\= x = 19$

The standard deviation is $\sigma = 1.7$

The level of significance is $\alpha = 0.001$

The null hypothesis is $H_o: \mu = 18$

The alternative hypothesis is $H_a : \mu > 18$

The critical value of the level of significance from the normal distribution table is

$Z_{\alpha } = 3.290527$

The test hypothesis is mathematically represented as

$t = \frac{\= x - \mu }{ \frac{\sigma}{ \sqrt{n} } }$

substituting values

$t = \frac{ 19 - 18}{ \frac{1.7}{ \sqrt{15} } }$

$t = 2.28$

Looking at the value of t and $Z_{\alpha }$ we can see that $t < Z_{\alpha }$ so we fail to reject the null hypothesis.

This mean that there is no sufficient evidence to support the professor believe

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4 years ago