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3 years ago

5p−9=2p+12 solve for p

Mathematics

2 answers:

joja [24]3 years ago

7 0

5p-9=2p+12
5p-2p=12+9
3p=21
p=21/3
p=7

vovikov84 [41]3 years ago

7 0

P=3
+9 on both sides cancels the 9 and makes it 7p=21
7 divided by 21 is 3
p=3

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A water pitcher contains 2/3 gallons of water you add 5/7 gallons of water to the picture how much water to the picture contain

Shtirlitz [24]

2/3=14/21 and 5/7=15/21 so 14/21+15/21=29/21 or 1 and 8/21

4 0

2 years ago

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What is the simplest form of 6 radical 8 plus 8 radical 2

arsen [322]

Answer:

20 $\sqrt{2}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplify

$\sqrt{8}$ = $\sqrt{4(2)}$ = $\sqrt{4}$ × $\sqrt{2}$ = 2 $\sqrt{2}$

Thus

6 $\sqrt{8}$ + 8 $\sqrt{2}$

= 6(2 $\sqrt{2}$ ) + 8 $\sqrt{2}$

= 12 $\sqrt{2}$ + 8 $\sqrt{2}$

= 20 $\sqrt{2}$

8 0

3 years ago

BC has a midpoint at M(6, 6). Point C is at (2, 10). Find the coordinates of point B.

agasfer [191]

Answer:

The coordinates of B are (10,2)

Step-by-step explanation:

Hi there!

We know that BC has a midpoint M, with the coordinates (6,6), and the endpoint C, with coordinates (2, 10)

We want to find the coordinates of point B

The midpoint formula is $(\frac{x_1 + x_2}{2}, \frac{y_1+ y_2}{2})$ , where $(x_1, y_1)$ and $(x_2 , y_2)$ are points. In this case, the point C has the values of $(x_1, y_1)$ , and B has the values of $(x_2 , y_2)$

We know that coordinates of M equal $(\frac{x_1 + x_2}{2}, \frac{y_1+ y_2}{2})$

In other words,

$\frac{x_1 + x_2}{2} = 6\\ \frac{y_1+ y_2}{2}=6$

Let's plug 2 for $x_1$ and 10 for $y_1$

So:

$\frac{2 + x_2}{2} = 6\\ \frac{10+ y_2}{2}=6$

Multiply both sides by 2

${2 + x_2} = 12\\{10+ y_2} =12$

Subtract 2 from both sides in the first equation to find the value of $x_2$ :

$x_2=10$

Now, for the second equation, subtract 10 from both sides to find the value of $y_2$

$y_2=2$

Now substitute these values for $(x_2, y_2)$

$(x_2, y_2)=(10,2)$

So the coordinates of point B are (10, 2)

Hope this helps!

3 0

3 years ago

1. Are we limited to using a trigonometric function only in cases of an object that has a cyclical behavior? Is it possible to m

pentagon [3]

Trigonometric functions are not only used in cases of an object that has a cyclical behavior.

<h3>What is a trigonometric function?</h3>

It should be noted that trigonometric functions are real functions that relate the angle of a right angled triangle to the ratios of the two side lengths.

Trigonometric functions are not only used in cases of an object that has a cyclical behavior. It can be used to obtain unknown <em>angles</em> in geometric figures.

It can also be used to model the fluctuations in temperature data for a particular year.

The movement of a yo-yo can be modeled by a sinusoidal curve since it exhibits a periodic behavior.

Learn more about trigonometry on:

brainly.com/question/24349828

4 0

1 year ago

50 POINTS! PLEASE HELP!

Sauron [17]

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your answer is C.x - 4

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7 0

3 years ago

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