Answer:
The P-value is 0.0166.
Step-by-step explanation:
<u>The complete question is:</u> In a one-tail hypothesis test where you reject H0 only in the lower tail, what is the p-value if ZSTAT = -2.13.
We are given that the z-statistics value is -2.13 and we have to find the p-value.
Now, the p-value of the test statistics is given by the following condition;
P-value = P(Z < -2.13) = 1 - P(Z
2.13)
= 1 - 0.9834 = <u>0.0166</u>
Assuming that the level of significance is 0.10 or 10%.
The decision rule for rejecting the null hypothesis based on p-value is given by;
- If the P-value of the test statistics is less than the level of significance, then we have sufficient evidence to reject the null hypothesis.
- If the P-value of the test statistics is more than the level of significance, then we have insufficient evidence to reject the null hypothesis.
Here, the P-value is more than the level of significance as 0.0166 > 0.10, so we have insufficient evidence to reject the null hypothesis, so we fail to reject the null hypothesis.
A.
2/3A=-24
time both sides by 3/2
A=-72/2
A=-36
B.
20=-B/0.2
times both sides by 0.2
4=-B
times -1
-4=B
distance between 2 points x and y is |x-y|
so
distance between A and B is distance between -4 and -72 or
|-72-(-4)|=|-72+4|=|-68|=68
the distance is 68
5 dollars a ticket. Divide 80/16 to get tour answer.
first, rewrite 54 as 6•9
next, rewrite 42 as 6•7
then, that gets you 6x^2 -6•7x- 6•9
lastly, factor out the common term (6)
and then you get 6(x^2-7x-9)
<u>please mark as brainliet <3</u>