Answer:
1500
Explanation:
Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.
The total population size of F2 generation = 2000
The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)
Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500
Answer: It is a product formed.
Reasoning: The plant uses the energy from the glucose to survive and to photosynthesize. Glucose is the product of photosynthesis.
Answer:
The osmolarity of mammalian urine may vary over time. The osmolarity of mammalian urine varies little between species. Mammalian urine is always hyperosmotic to blood. The osmolarity of mammalian urine may vary over time.
Explanation:
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Answer:
The answer is option 1 about 70% of total global carbon is found in oceans.
Explanation:
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