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3 years ago

If c=3 what is the answer for c to the third power/2

Mathematics

2 answers:

erik [133]3 years ago

6 0

Answer:

Step-by-step explanation:

erastovalidia [21]3 years ago

6 0

The answer to your question is 9 because 3 multiply by 3 is equal to 9.

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2 years ago

Which is bigger 1/10 1/12

nasty-shy [4]

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3 years ago

Read 2 more answers

The diameter of a circle is 6 in. Find its area to the nearest tenth.

Marrrta [24]

Answer and Step-by-step explanation:

The area formula for a Circle is:

A = $\pi r^2$

Diameter is equal to the radius times 2.

So, divide the diameter to get the radius.

6 divided by 2 equals 3.

Now, plug it into the formula.

$A = \pi (3)^{2}$

A = $9\pi$

Plug this into your calculator by multiplying 9 by pi.

We get the answer to be 28.3 when rounded to the nearest tenth.

#teamtrees #PAW (Plant And Water)

8 0

2 years ago

PLEASE HELP I WILL GIVE A LOT OF POINTS!

vazorg [7]

9514 1404 393

Answer:

(2.27, 0.96)

Step-by-step explanation:

The orthocenter is the point of intersection of altitudes of the triangle. The equation for an altitude is the equation of a line through a vertex that is perpendicular to the opposite side.

For example, the line perpendicular to side AC can be found as ...

(∆x, ∆y) = C-A = (3, -1) -(-4, 2) = (7, -3)

∆x(x -h) +∆y(y -k) = 0 . . . . perpendicular through point (h, k)

For side AC, we want the point to be B(4, 5), so the equation is ...

7(x -4) -3(y -5) = 0

7x -3y -13 = 0

Similarly, the altitude to side AB can be written as ...

(∆x, ∆y) = B -A = (4, 5) -(-4, 2) = (8, 3)

8(x -3) +3(y +1) = 0

8x +3y -21 = 0

By the "cross multiplication method", the solution to these equations is ...

x = (-3(-21) -(3(-13))/(7(3) -8(-3)) = (63+39)/(21+24) = 102/45 = 2 4/15 ≈ 2.27

y = (-13(8) -(-21)(7))/45 = 43/45 ≈ 0.96

The orthocenter is near (2.27, 0.96).

A graphing application confirms this result.

_____

Additional information about the cross multiplication method

For the general form equations ...

ax +by +c = 0
dx +ey +g = 0

The "cross multiplication method" has you write the array ...

$\begin{array}{cccc}a&b&c&a\\d&e&g&d\end{array}$

and form the "cross products" in groups of four coefficients:

D = ae -db, X = bg -ec, Y = cd -ga

Then the solution to the set of equations is ...

1/D = x/X = y/Y ⇒ x = X/D, y = Y/D

Additional note

Videos of this method show you writing the array as bcab/egde and using the final equation x/X=y/Y=1/D. The above gets the same result in a more straightforward manner.