You didn’t post the chart
Answer:
legth of life is the answer
Answer:
20 chromosomes
Explanation:
Mitosis is a kind of cell division that results in daughter cells with same number of chromosomes as the parent cell. It involves stages including Prophase, Metaphase, Anaphase and Telophase. In prophase, the Chromatin condenses into Chromosomes.
In Anaphase stage, the 10 chromosomes as mentioned in the question divides into opposite poles of the cell. One individual chromosome contains two sister chromatids, which actually separates in the Anaphase stage. Hence, at the end of the Anaphase stage, there will be 10 chromatids each at opposite poles of the cell. Each chromatid at this stage is considered a chromosome.
Hence, a cell with 10 chromosomes will contain 20 chromosomes (10+10 chromatids on each pole) in the Anaphase stage just before the cell divides into two in a process called CYTOKINESIS.
Admitting that the "a" is a capital A for normal pigmentation and "d" is a capital D for dimpled chin, meaning that these are the dominant traits, the fraction expected to be albino with a non-dimpled chin is of 1/16.
When two heterozygous are crossed and two characteristics are being analysed, the offspring quantity that will possess the two recessive traits can be represented by 1/16. This is easily confirmed when a Punnett square is made. Considering that both parents were heterozygous, on both sides of the crossing in the Punnett square, you would have the following alleles' combination: AD, Ad, aD, and ad. The offspring that would be homozygous recessive (aadd) would correspond to only 1/16.
