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anygoal [31]
3 years ago
9

Can you please help me with this problem?

Mathematics
2 answers:
Oduvanchick [21]3 years ago
4 0
Volume of rectangular prism = 4.5*5*2.5=56.25cm^3
bazaltina [42]3 years ago
4 0
To find the volume you have to multiply 2 1/2x4 1/2x5 which is 56.25 and as a fraction it’s 56 1/4
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A certain westbound U.S. highway truck route near a river has a downhill grade of 9%. (a) Explain what a 9% downhill grade means
pashok25 [27]

Answer:

A) A 9% downhill grade means that the decrease in elevation of the road over the segment is 9% of the change in Horizontal distance over the same segment. In other words, for every 100 horizontal feet the road descends 9 feet and the road has a slope of 0.09 vertical feet per horizontal foot.

Step-by-step explanation:

A Certain westbound U.S highway truck route near a river has a downhill grade of 9%

A) A 9% downhill grade means that the decrease in elevation of the road over the segment is 9% of the change in Horizontal distance over the same segment. In other words, for every 100 horizontal feet the road descends 9 feet and the road has a slope of 0.09 vertical feet per horizontal foot.

In other to make things clear, lets assume

for X = 1 , y = 9% = 0.09

for y =  9 , x = 9 / 0.09 = 100

slope = y/x = 0.09 / 1 = 0.09

5 0
3 years ago
Which of the following is the equation of a circle with a radius of 10 cm and center at (–3, 6)?
Volgvan

The equation of the circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have:

r=10\\(-3,\ 6)\to h=-3,\ k=6

Substitute:

(x-(-3))^2+(y-6)^2=10^2\\\\(x+3)^2+(y-6)^2=100

4 0
3 years ago
Identify the three similar triangles in the figure. Be sure to name the vertices in the correct order
Sonja [21]

Answer:

BDC  and ADB

Step-by-step explanation:

6 0
2 years ago
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Oxana [17]
Answer:

Geela would need 9 yellow parts


Explanation:

Originally, the Geela needed more yellow than red and the difference was 4 parts.

6-2=4 parts


4 parts + 5 parts of yellow = 9 yellow parts.
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amm1812
The answer : 2x + y^2
4 0
3 years ago
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