Question

A triangle has an area of 1102 m², and two of the sides of the triangle have lengths 60 m and 56 m. find the angle included by these two sides.

Answer 1

A = (1/2)*a*b*sin(C)
1102 m^2 = (1/2)*(60 m)*(56 m)*sin(C)
2*1102/(60*56) = 551/840 = sin(C)
C = arcsin(551/840) ≈ 41°