Answer:
There are 1.8021 ⋅ 1024 molecules of CH4 in 48 grams of CH4. To answer this question, you must understand how to convert grams of a molecule into the number of molecules. To do this, you have to utilize the concepts of moles and molar mass. A mole is just a unit of measurement. Avogadro's number is equal to 6.022 ⋅1023 molecules/mole. i think please dont complain to me if its wrong im sorry
Explanation:
In a gas, the partcles are very far apart and loose.
Answer:
Explanation:
-We convert Ca(OH)₂ grams to moles using its <em>molar mass</em>:
- 31.82 g ÷ 74.093 g/mol = 0.43 mol
-We convert K₂SO₃ moles to grams using its <em>molar mass</em>:
- 3.2 mol * 158.26 g/mol = 506.4 g
-One formula unit of HCl is HCl. We convert molecules to moles using <em>Avogadro's number</em>:
- 7.25x10²³ molecules ÷ 6.023x10²³mol/molecules = 1.20 mol
-At STP, <em>one mol of any gas occupies 22.4 L</em>:
- 46.6 L * 1 mol / 22.4 L = 2.080 mol
The volume of CO2 at STP =124.298 L
<h3>Further explanation</h3>
Given
Reaction
4 KMnO4, +4 C3H5(OH)5, -7K2CO3, + 7 Mn2O3, +5 CO2, + 16 H2O
701,52 g of KMnO4
Required
volume of CO2 at STP
Solution
mol KMnO4 (MW=158,034 g/mol) :
mol = mass : MW
mol = 701.52 : 158.034
mol = 4.439
mol CO2 from equation : 5/4 x mol KMnO4 = 5/4 x 4.439 = 5.549
At STP 1 mol = 22.4 L, so for 5.549 moles :
=5.549 x 22.4
=124.298 L