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3 years ago

Potassium permanganate, KMnO, and glycerin, C3H5(OH)3, react explosively according to the

Chemistry

1 answer:

Finger [1]3 years ago

4 0

The volume of CO2 at STP =124.298 L

<h3>Further explanation</h3>

Given

Reaction

4 KMnO4, +4 C3H5(OH)5, -7K2CO3, + 7 Mn2O3, +5 CO2, + 16 H2O

701,52 g of KMnO4

Required

volume of CO2 at STP

Solution

mol KMnO4 (MW=158,034 g/mol) :

mol = mass : MW

mol = 701.52 : 158.034

mol = 4.439

mol CO2 from equation : 5/4 x mol KMnO4 = 5/4 x 4.439 = 5.549

At STP 1 mol = 22.4 L, so for 5.549 moles :

=5.549 x 22.4

=124.298 L

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calculate the mass of calcium phosphate and the mass of sodium chloride that could be formed when a solution containing 12.00g o

Leviafan [203]

Answer : The mass of calcium phosphate and the mass of sodium chloride that formed could be, 9.3 and 10.5 grams respectively.

Explanation : Given,

Mass of $Na_3PO_4$ = 12.00 g

Mass of $CaCl_2$ = 10.0 g

Molar mass of $Na_3PO_4$ = 164 g/mol

Molar mass of $CaCl_2$ = 111 g/mol

Molar mass of $NaCl$ = 58.5 g/mol

Molar mass of $Ca_3(PO_4)_2$ = 310 g/mol

First we have to calculate the moles of $Na_3PO_4$ and $CaCl_2$ .

$\text{Moles of }Na_3PO_4=\frac{\text{Given mass }Na_3PO_4}{\text{Molar mass }Na_3PO_4}$

$\text{Moles of }Na_3PO_4=\frac{12.00g}{164g/mol}=0.0732mol$

and,

$\text{Moles of }CaCl_2=\frac{\text{Given mass }CaCl_2}{\text{Molar mass }CaCl_2}$

$\text{Moles of }CaCl_2=\frac{10.0g}{111g/mol}=0.0901mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is:

$2Na_3PO_4+3CaCl_2\rightarrow 6NaCl+Ca_3(PO_4)_2$

From the balanced reaction we conclude that

As, 3 mole of $CaCl_2$ react with 2 mole of $Na_3PO_4$

So, 0.0901 moles of $CaCl_2$ react with $\frac{2}{3}\times 0.0901=0.0601$ moles of $Na_3PO_4$

From this we conclude that, $Na_3PO_4$ is an excess reagent because the given moles are greater than the required moles and $CaCl_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NaCl$ and $Ca_3(PO_4)_2$

From the reaction, we conclude that

As, 3 mole of $CaCl_2$ react to give 6 mole of $NaCl$

So, 0.0901 mole of $CaCl_2$ react to give $\frac{6}{3}\times 0.0901=0.1802$ mole of $NaCl$

and,

As, 3 mole of $CaCl_2$ react to give 1 mole of $Ca_3(PO_4)_2$

So, 0.0901 mole of $CaCl_2$ react to give $\frac{1}{3}\times 0.0901=0.030$ mole of $Ca_3(PO_4)_2$

Now we have to calculate the mass of $NaCl$ and $Ca_3(PO_4)_2$

$\text{ Mass of }NaCl=\text{ Moles of }NaCl\times \text{ Molar mass of }NaCl$

$\text{ Mass of }NaCl=(0.1802moles)\times (58.5g/mole)=10.5g$

and,

$\text{ Mass of }Ca_3(PO_4)_2=\text{ Moles of }Ca_3(PO_4)_2\times \text{ Molar mass of }Ca_3(PO_4)_2$

$\text{ Mass of }Ca_3(PO_4)_2=(0.030moles)\times (310g/mole)=9.3g$

Therefore, the mass of calcium phosphate and the mass of sodium chloride that formed could be, 9.3 and 10.5 grams respectively.

5 0

3 years ago

A balloon that contains 0.750 moles of gas has a volume of 16.8 L. If additional gas causes the balloon to expand to a volume of

mixas84 [53]

the answer is 1.13 moles

5 0

3 years ago

Read 2 more answers

Compared to other stars we observe, the Sun appears bigger and brighter because:

Kipish [7]

Answer:

Compared to other stars we observe, the Sun appears bigger and brighter because it is much closer to earth.

Objects closer to earth appear to be much bigger and brighter.

Let me know if this helps!

3 0

3 years ago

Read 2 more answers

How many moles are there in 111.7 g of Fe?

Alenkinab [10]

Answer:

Explanation:

55.85 grams per mole.

times 2

111.7

6 0

3 years ago

What’s the answer????

dezoksy [38]

Should be , b
. Not positive tho

8 0

3 years ago