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liraira [26]
3 years ago
12

How many molecules are there in 45.0 grams of CH ?

Chemistry
1 answer:
Sonbull [250]3 years ago
8 0

Answer:

There are 1.8021 ⋅ 1024 molecules of CH4 in 48 grams of CH4. To answer this question, you must understand how to convert grams of a molecule into the number of molecules. To do this, you have to utilize the concepts of moles and molar mass. A mole is just a unit of measurement. Avogadro's number is equal to 6.022 ⋅1023 molecules/mole. i think please dont complain to me if its wrong im sorry

Explanation:

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A substance with a definite volume and a definite shape is classified as a what?
sergeinik [125]

Answer:

Solids

Explanation:

It can be found

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What determines which element an atom is?
Lana71 [14]
C) number of protons.
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How many significant digits does the number 700 have?
OLga [1]

Answer: 700 has one significant figure which is 7.

Explanation: These are some rules for significant figures

•All non-zero digits are significant: 1,2,3,4,5,6,7,8,9

•Zero between non-zero digits are significant: They are three significant figures in 203.

•Leading zeros are not significant: There are two significant figures in 0.56.

•Trailing zero to the right of decimal are significant. There are four significant figures in 62.00

•Trailing zeros in a whole number with the decimal shown are significant: This makes "700." three significant figures.

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A student mixed two chemicals to allow them to
Westkost [7]

Answer:

B .it is an exothermic reaction

Explanation:

i need brainleyest

4 0
2 years ago
2-A gas sample is found to contain 39.10% carbon, 7.67% hydrogen, 26.11%
aleksandrvk [35]

The molecular formula :

C₆H₁₄O₃PF

<h3>Further explanation</h3>

Given

39.10% carbon, 7.67% hydrogen, 26.11%  oxygen, 16.82% phosphorus, and 10.30% fluorine.

Required

The molecular formula

Solution

mol ratio :

C = 39.1 : 12 = 3.258

H = 7.67 : 1 = 7.67

O = 26.11 : 16 = 1.632

P = 16.82 : 31 = 0.543

F = 10.3 : 19 = 0.542

Divide by 0.542

C = 6

H : 14

O = 3

P = 1

F = 1

The empirical formula :

C₆H₁₄O₃PF

(The empirical formula)n = the molecular formula

(C₆H₁₄O₃PF)=184.1

(6.12+14.1+3.16+31+19)n=184.1

(184)n=184.1

n = 1

3 0
3 years ago
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