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Digiron [165]
3 years ago
12

What is the length of side BC of the triangle? Enter your answer in the box. units Triangle A B C with horizontal side B C. Vert

ex A lies above side B C. Angle B and angle C are marked congruent. The length of side A C is labeled as x plus 8. The length of side A B is labeled as 2 x minus 1. The length of side B C is labeled as 3 x minus 3.
Mathematics
2 answers:
larisa [96]3 years ago
5 0

Answer:  Length of BC = 24 units.

Explanation:


Given that in triangle ABC, BC is the base, and angle B = angle C

SInce two angles are equal, ABC is isosceles with sides AB = AC

Given that AC = x+8 and AB = 2x-1

Since AB = AC we get these two are equal.  Use this t solve for x.

x+8 = 2x-1

x =9.

It is easy to find BC now.

BC =3x-3

Hence BC =3(9)-3 = 24

Length of BC= 24 units.

Marysya12 [62]3 years ago
5 0

Answer:

24 unites

Step-by-step explanation:

Given that in triangle ABC, BC is the base, and angle B = angle C

SInce two angles are equal, ABC is isosceles with sides AB = AC

Given that AC = x+8 and AB = 2x-1

Since AB = AC we get these two are equal.  Use this t solve for x.

x+8 = 2x-1

x =9.

It is easy to find BC now.

BC =3x-3

Hence BC =3(9)-3 = 24

Length of BC= 24 units.

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Please help 60 points!!
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Answer:

The answer to your question is FJ = 18

Step-by-step explanation:

Data

FG = 30

FH = 12

HE = 8

JH ║GE

These triangles are similar, so we can use proportions to find the length of FJ.

                            \frac{FJ}{FH} = \frac{FG}{FH + HE}

Substitution

                          \frac{FJ}{12} = \frac{30}{12 + 8}

Simplification

                         \frac{FJ}{12} = \frac{30}{20}

Solve for FJ

                        FJ = 12 \frac{30}{20}

Result

                        FJ = 18

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