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3 years ago

Five cats each ate 1/4 cup of cat food. How much food did the five cats eat?

Mathematics

1 answer:

qaws [65]3 years ago

7 0

Answer: Five cats ate 1 and a quarter of cat food.

Step-by-step explanation

Given:-

Cat food ate by one cat = 1/4 cup

Cat food ate by five cats = $5\times \frac{1}{4} \text{ [Multiplying both sides with 5 ]}\\\\=\frac{5}{4}=\frac{4+1}{4}=\frac{4}{4}+\frac{1}{4}=1+\frac{1}{4}$ =1 and 1/4 cup.

Therefore cat food ate by five cats = 1 and a quarter of cup.[ here a quarter =1/4]

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40287600 = B. 4 x $10^{7}$

Step-by-step explanation:

<u>We first have to do the multiplication of the numbers given:</u>

19 * 2,120,400

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3 years ago

Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of

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Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

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$A(t) = A(0)(1-r)^t$

$0.74A(0) = A(0)(1-r)^{24}$

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$\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}$

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$1 - r = 0.9875$

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The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that $A(0) = 810$

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

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$A(t) = A(0)(1-r)^t$

$A(t) = 810(1 - 0.26)^t$

$A(t) = 810(0.74)^t$

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

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