The function h ( x ) = 1 x − 1 h ( x ) = 1 x - 1 can be expressed in the form f ( g ( x ) ) f ( g ( x ) ) , where g ( x ) = ( x
− 1 ) g ( x ) = ( x - 1 ) , and f ( x ) f ( x ) is defined as:
1 answer:
Answer: f(x) = 1^(x + 1)
Step-by-step explanation:
we have that h(x) = 1^x
and h(x) = f(g(x))
This mean that we are evaluating the function f(y) in the point y = g(x)
where g(x) = x - 1
then:
f(g(x) = f(x - 1) = h(x) = 1^x
then we should have that:
f(x) = 1^(x + 1)
then:
f(x - 1) = 1^(x - 1 + 1) = 1^x
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