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3 years ago

[ Please Help! ]

Mathematics

1 answer:

denis-greek [22]3 years ago

3 0

answer for part 4 is attached below

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0.6 : 3.3 : 3/2 reduce this the : means its a ratio REDUCE THE RATIO!!!

Sati [7]

3:5
1:1
1.5 or 1:5 not sure

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3 years ago

Make a comparison true. Drag and drop tenth value to fill in the blank. Select all that apply. 24. _ > 24. 34

spayn [35]

Answer:

Step-by-step explanation:

These items may be used by Louisiana educators for educational purposes. Grade 7 Answer Key. ITEM 14. Use the table to answer the question.

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2 years ago

4. 4c - 3 (c = -2) will give 5 stars

Flauer [41]

4(-2)-3 = -8-3 = -11
Answer: -11

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3 years ago

For each of the following binomial random variables, specify n and p. (a) A fair die is rolled 50 times. X = number of times a 5

Keith_Richards [23]

Answer:

a) $n = 50, p = \frac{1}{6}$

b) $n = 16, p = \frac{1}{100}$

c) $n = 26, p = 0.25, \mu = 6.5$

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $p$ is the probability of X happening.

(a) A fair die is rolled 50 times. X = number of times a 5 is rolled

The die is rolled 50 times, so $n = 50$ .

Each roll can have 6 outcomes. So the probability that 5 is rolled is $p = \frac{1}{6}$

(b) A company puts a game card in each box of cereal and 1/100 of them are winners. You buy sixteen boxes of cereal, and X = number of times you win.

You buy 16 boxes of cereal, so $n = 16$ .

1 of 100 are winners. So $p = \frac{1}{100}$ .

(c) Jack likes to play computer solitaire and wins about 25% of the time. X = number of games he wins out of his next 26 games.

He plays 26 games, so $n = 26$ .

He wins 25% of the time, so $p = 0.25$

We have that $\mu = np$ . So $\mu = 26*0.25 = 6.5$

6 0

4 years ago

A transformer increases the input voltage from 12V to 12,000V. What is the ratio of the number of wire turns on the primary coil

erma4kov [3.2K]

Answer:

$\frac{n_p}{n_s}=\frac{1}{1000}$

Step-by-step explanation:

Given voltage of primary coil is $V_p=12V$

And voltage of secondary coil is $V_s=12,000V$

A transformer is a device that contains primary and secondary coil. These coils are mounted on soft iron. The change in voltage depends upon the number of turns of primary coil $(n_p)$ and secondary coil $(n_s)$ .

Following equation represents the relation between them.

$\frac{V_s}{V_p} =\frac{n_s}{n_p}\\\\\frac{12,000}{12}=\frac{n_s}{n_p}\\\\1000=\frac{n_s}{n_p}$

Then, ratio of the number of wire turns on the primary coil to the number of turns on the secondary coil is

$\frac{n_p}{n_s}=\frac{1}{1000}$

5 0

4 years ago