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raketka [301]
4 years ago
6

A 10-g bullet moving horizontally with a speed of 1.8 km/s strikes and passes through a 5.0-kg block initially at rest on a hori

zontal frictionless surface. The bullet emerges from the block with a speed of 1.0 km/s. What is the kinetic energy of the block immediately after the bullet emerges? a. 8.0.J 6.4 J 5.3 J 9.4 J 10 J e.
Physics
1 answer:
UNO [17]4 years ago
4 0

Answer:

6.4 J

Explanation:

m = mass of the bullet = 10 g = 0.010 kg

v = initial velocity of bullet before collision = 1.8 km/s = 1800 m/s

v'  = final velocity of the bullet after collision = 1 km/s = 1000 m/s

M = mass of the block = 5 kg

V = initial velocity of block before collision = 0 m/s

V'  = final velocity of the block after collision = ?

Using conservation of momentum

mv + MV = mv' + MV'

(0.010) (1800) + (5) (0) = (0.010) (1000) + (5) V'

V' = 1.6 m/s

Kinetic energy of the block after the collision is given as

KE = (0.5) M V'²

KE = (0.5) (5) (1.6)²

KE = 6.4 J

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Tasya [4]

Average velocity is defined as the ratio in change in position to change in time,

v[ave] = ∆x/∆t

which on its own doesn't have anything to do with acceleration.

<u>If acceleration is constant</u>, the average velocity is the literal average of the initial and final velocities,

v[ave] = (v[final] + v[initial]) / 2

If this constant acceleration has magnitude a, the final velocity can be expressed in terms of the initial velocity by

v[final] = v[initial] + a*t

and plugging this into the previous equation gives

v[ave] = (v[initial] + a*t + v[initial])/2

v[ave] = v[initial] + 1/2*a*t

If the body in consideration is <u>initially at rest</u>, then

v[ave] = 1/2*a*t

which might be the relation you're looking for. But bear in mind the conditions I've underlined.

<u>If acceleration is not constant and changes over time</u>, so that the acceleration is some function of time a(t), then you can determine the velocity function v(t) by using the fundamental theorem of calculus. You need to know a particular velocity for some time to completely characterize v(t), though. For example, if you're given the initial velocity v[initial] = v(0), then

\displaystyle v(t) = v(0) + \int_0^t a(u) \, du

or if you know any other velocity for some time t₀ > 0,

\displaystyle v(t) = v(t_0) + \int_{t_0}^t a(u) \, du

8 0
3 years ago
Which of the following statements are true?
Tems11 [23]

Answer:

1) A time-varying magnetic field will produce an electric field.

4) A time-varying electric field will produce a magnetic field.

Explanation:

1) A time-varying magnetic field will produce an electric field.

TRUE

time varying magnetic field will produce electric field which is given as

E = \frac{r}{2}\frac{dB}{dt}

2) Time-varying electric and magnetic fields can propagate through space only if there is no matter in their path.

FALSE

Time varying electric field and magnetic field will induce each other and it can travel through any medium as well as it can travel without any medium also

3) Electric and magnetic fields can be treated independently only if they vary in time.

FALSE

electric field can be due to stationary charge and magnetic field due to current carrying elements so it is not compulsory to have time varying

4) A time-varying electric field will produce a magnetic field.

TRUE

Time varying electric field will produce magnetic field given as

B = \frac{\mu_o\epsilon_o A}{2r}\frac{dE}{dt}

3 0
3 years ago
A child is holding a wagon from rolling straight back down in a driveway that inclined at 20 degree horizontal. if the wagon wei
Digiron [165]

Answer:

F = 51.3°

Explanation:

The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:

F = Parallel\ Component\ of\ Weight\ of\ Wagon= WSin\theta\\

where,

W = Weight of Wagon = 150 N

θ = Angle of Inclinition = 20°

Therefore,

F = (150\ N)Sin\ 20^o

<u>F = 51.3°</u>

5 0
3 years ago
How many leptons are in ⁷₃Li?
shutvik [7]

-- Electrons are leptons.  There are <em>three</em> electrons in each neutral Lithium atom.

The last two parts of the question are absurd.

-- Bonbons are candy, not atomic particles.  A bonbon cannot fit into a Lithium atom.

-- A pentagon is a closed geometric figure that has five sides.  Although you could, in principle, have a pentagon small enough to fit into a Lithium atom, you could never find a piece of paper small enough to draw it on.

5 0
3 years ago
The specific heat of a solid Y is 11.5 cal/g°C. A sample of this
fgiga [73]

The sample of the solid in grams is 5.5g

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

  • The quantity of heat absorbed or released by a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

Q = quantity of heat absorbed/released (cal)

m = mass of the substance (g)

c = specific heat (cal/g°C)

∆T = change in temperature (°C)

  • According to the information provided in this question:

Q = 7.90Kcal = 7900cal

m = ?

c = 11.5 cal/g°C

T1 = 135K = 135K − 273.15 = -138.1°C

T2 = 260K = 260K − 273.15 = -13.15°C

∆T = -13.15 - (-138.1) = 124.95°C

  • Hence, the mass of the substance can be calculated as follows:

m = Q ÷ c∆T

m = 7900 ÷ (11.5 × 124.95)

m = 7900 ÷ 1436.93

m = 5.5grams.

Therefore, the sample of the solid in grams is 5.5g.

Learn more: brainly.com/question/21643161?referrer=searchResults

5 0
2 years ago
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