B. 500ft. If you are driving at night with high beams on you must dim them within 500 feet of an oncoming vehicle.
Answer:
Fx1 (6 m) sin 60 = 300 (3 m) cos 60 balancing torques about floor
Fx1 = 900 * 1/2 / 5.20 = 86.6 N this is the horizontal force that must be supplied by the wall to balance torques about the floor
This is also equal to the static force of friction that must be applied at the point of contact with the floor to balance forces in the x-direction.
Fx1 = Fx2 = 86.6 N
The work is 90 as 5 times 18
Answer: 2.1 × 10^7 m/s
Explanation:
Please see the attachments below