The Solution for the given system of equations is (-2) and 
.
The given are linear equations as follow:
y = 
+ 3 .. ... ...(1)
and x = -2. .. .... ...(2)
We already know the first part of the solution (x) which is -2. We can find the other part (y) by putting the value of equation (2) in equation (1).
By putting the values of x in equation (1), we get
y = 
+ 3
y = 
+ 3
Taking the L. C. M of denominators which will be '3', we get:
y = 
y = 
So the second part (y) of the solution of the given equation is .
Hence, the overall solution to the given system of equation is 
.
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Answer:
hypotenuse is 22.47 m
Step-by-step explanation:
The length of both legs of a right angle triangle are 8m and 21 m
We need to find the hypotenuse
To find hypotenuse we use Pythagorean theorem
Hypotenuse is AC and other two legs are AB and BC
Hypotenuse ^2 = 8^2 + 21^2
hypotenuse = 
= 
= 
= 22.47
So the length of the hypotenuse is 22.47 m
Area = 7(x + 2) = 7x + 14
Perimeter = 2(7 + x + 2) = 2(9 + x) = 18 + 2x
7x + 14 > 18 + 2x
7x - 2x > 18 - 14
5x > 4
x > 4/5
A x = 0
using the law of exponents 
= 1
for (6² )^ x = 1 then x = 0
B note that 
= 1 ⇒ x = 1
2 → 2^8 × 3^(-5) × 1^(-2) × 3^(-8) × 2^(-12) × 2^(28)
= 2^(8 -12 + 28) × 1 × 3^(- 5 - 8)
= 2^24 × 3^(- 13) = 2^(24)/3^(13) = 10.523 ( 3 dec. places)
