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3 years ago

I need help for this multiply choice geometry problem

Mathematics

1 answer:

Misha Larkins [42]3 years ago

5 0

Answer:

Answer B

Step-by-step explanation:

As we can see in the figure, AB is parallel with DE, AE and BD intersect each other at point C.

=> So that ACB and ECD are two congruent triangles.

According to the features of two congruent triangles, we have:

AC/EC = CB/CD = AB/ED

=> 4/8 = 3/6 = AB/ ED

=> AB/ ED = 1/2

=> AB = 1/2 ED

=> AB = 1/2 x 3

=> x= 0.5

So the value of x if 1.5

Correct answer is B

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-.25 x+1.3=-.55x-.2 find x

Mamont248 [21]

You need to isolate the variable my dividing each side by factors that don’t contain the variable
x=-5

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3 years ago

What is the solution to this fraction problem

Zina [86]

Answer:

ABCD

Step-by-step explanation:

so first you use glue and then paint and then contact solution

4 0

2 years ago

It costs more to produce defective items - since they must be scrapped or reworked - than it does to produce non-defective items

Shtirlitz [24]

Answer:

1,082

Step-by-step explanation:

The sample size n in Simple Random Sampling is given by

$\bf n=\frac{z^2s^2}{e^2}$

where

z = 1.645 is the critical value for a 90% confidence level (*)

s = 2 is the estimated population standard deviation

e = 0.1 mm points is the margin of error

$\bf n=\frac{z^2s^2}{e^2}=\frac{(1.645)^2(2)^2}{(0.1)^2}=1,082.22\approx 1,083$

rounded up to the nearest integer.

So the manufacturer should test 1,083 parts.

---------------------------------------------------------------------------------------

(*)This is a point z such that the area under the Normal curve N(0,1) outside the interval [-z, z] equals 10% = 0.1

It can be obtained in Excel with

NORMINV(1-0.05,0,1)

and in OpenOffice Calc with

NORMINV(1-0.05;0;1)

5 0

3 years ago

Find the work (in ft-lb) required to pump all the water out of a cylinder that has a circular base of radius 7 ft and height 200

Virty [35]

Answer:

work done is equal to 384279168 lb-ft

Step-by-step explanation:

The cylinder has a circular base of 7 ft.

The height of the cylinder is 200 ft

The weight density of water in the cylinder is 62.4 lb/ft^3

First, we find the volume of the water in the cylinder by finding the volume of this cylinder occupied by the water.

The volume of a cylinder is given as $\pi r^{2} h$

where, r is the radius,

and h is the height of the cylinder.

the volume of the cylinder = $3.142* 7^{2}*200$ = 30791.6 ft^3

Since the weight density of water is 62.4 lb/ft^3, then, the weight of the water within the cylinder will be...

weight of water = 62.4 x 30791.6 = 1921395.84 lb

We know that the whole weight of the water will have to be pumped out over the height of cylindrical container. Also, we know that the work that will be done in moving this weight of water over this height will be the product of the weight of water, and the height over which it is pumped. Therefore...

The work done in pumping the water out of the container will be

==> (weight of water) x (height of cylinder) = 1921395.84 x 200

==> work done is equal to 384279168 lb-ft

7 0

3 years ago

X to the third plus x minus 7 equals -3 square root of x - 1

Ugo [173]

Answer:

x ≈ 1.5004

Step-by-step explanation:

We suppose your equation is ...

$x^3+x-7=-3\sqrt{x-1}$