Question

A container of water is lifted vertically 3.0 m then returned to its original position. If the total weight is 30 N, how much work total was done?

Answer 1

Answer: No work was done when a container of water is lifted vertically 3.0 m and then returned to its original position.

Explanation:

Work is defined as a force causing the movement or displacement of an object.

work=$f\times s$

Given: f = force = 30N

s = displacement = 0.0 m (as the initial and final position is same, there is no displacement)

Putting in the values we get,

work=$30N\times 0m=0J$

Thus amount of work will be 0 J.

Answer 2

Answer:

Work done, W = 0

Explanation:

Given that, a container of water is lifted vertically 3.0 m then returned to its original position.The total weight of the container is 30 N. We need to find the total work done by the container. We know that the work done by an object is given by :

W = F × d

Where

F is the applied force

d is the displacement of the object

It is mentioned that the container returns to its original position, the displacement of the container is equal to 0. Hence, no work was done by the container of water.