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Nastasia [14]
3 years ago
8

Which of the following planets helped astronomers locate another planet?

Physics
1 answer:
worty [1.4K]3 years ago
6 0

Answer: Pluto,Mercury

Explanation:

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Evaluate tan45/tan45
SIZIF [17.4K]

I'm not sure I completely understand the expression you want evaluated.

It looks like a fraction with the same exact thing in both the numerator and the denominator. A fraction like that always boils down to ' 1 '.

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• Can you explain why scientific theories will change over time?
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3 years ago
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Assume that the Deschutes River has straight and parallel banks and that the current is 0.75 m/s. Drifting down the river, you f
DedPeter [7]

Answer:

    d = 142.5 m

Explanation:

This is a vector exercise. Let's calculate how much the boat travels in the 40s

     d₀ = v_{b} t

    d₀ = 0.75 40

    d₀ = 30 m

Let's write the kinematic equations

Boat

     x = d₀  +  v_{b} t

     x = 0 +  v_{h} t

At the meeting point the coordinate is the same for both

    d₀  +  v_{b} t =  v_{h} t

    t ( v_{h} -  v_{b}) = d₀  

    t = d₀  / ( v_{b}-  v_{h})

The two go in the same direction therefore the speeds have the same sign

     t = 30 / (0.95-0.775)

     t = 150 s

The distance traveled by man is

     d =  v_{h} t

     d = 0.95 150

     d = 142.5 m

3 0
4 years ago
A rotating wheel requires 5.00 s to rotate 28.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 96.0 rad/
torisob [31]

Answer:

The constant angular acceleration of the wheel is 12.16 rad/s²

Explanation:

Given;

initial angular distance, θ = 28

time of the motion, t = 5 s

initial angular velocity is calculated as;

\omega _i = \frac{\theta}{t} = \frac{28}{5}.\frac{rev}{s}  \ \times \ \ \frac{2 \pi \ rad}{1 \ \ rev} = 35.19 \ rad/s

final angular velocity is given as, \omega _f = 96.0 \ rad/s

The constant angular acceleration is calculated as;

\alpha = \frac{\omega _f - \omega _i}{t} \\\\\alpha = \frac{96 - 35.19}{5} \\\\\alpha =  12.16 \ rad/s^2

Therefore, the constant angular acceleration of the wheel is 12.16 rad/s²

6 0
3 years ago
The region around a magnet where the magnetic force is exerted is known as
Olenka [21]
<span>The region around a magnet where the magnetic force is exerted is known as the </span>magnetic field.
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