<span>Applied Force Direction vector = [0,1,3]
force F = j + 4k
torque is t = 100 Newton-meters = r x F
Wrench is 0.5 meters long on positive side of the y-axis, r = 0.6 = [0,0.6,0]
We know torque |t| = |r x F| = |r| x |F| sin theta
r x F = |r| x |F| cos theta
r x (j + 3k) = |r| x |j + 3k| cos theta
=> [0,0.6,0] [0,1,3] = 0.6 x squareroot of ((0)^2 + (1)^2 + (3)^2) cos theta
=> 0.6 = 0.6 x squareroot of (1 + 9) cos theta
=> cos theta = 1 / squareroot of (10)
Calculationg the sin theta,
sin theta = squareroot of (1 - (1 / squareroot of (10))^2) = squareroot of (9/10)
sin theta = 3 / squareroot of (10)
Substituting the values,
|T| = |r| x |F| sin theta => 100 = |0.6| x |F| x 3 / squareroot of (10)
|F| = (100 x squareroot of (10)) / 1.8
|F| = (1000 / 18) x squareroot of (10)
Magnitude of force |F| = 55.55 x squareroot of (10)</span>
We know, U = m * g * h
U = 4000 * 9.8 * 20
U = 784000 J
In short, Your Answer would be: 784000 J or 784 KJ
Hope this helps!
Answer:
Velocity
Explanation:
the speed of something in a given direction
Answer:
The magnitud of the torque doing by the foot at the point where the shaft is attached is 0.063 Nm
Explanation:
The torque is obtained by multiplying the longitude from the shaft attached point to force acting point by the force perpendicular component:
T = d * Fp
Notice that the perpindicular component is the total force magnitud times the sino of the angle respect the horizontal:
Fp = F*sin(a)
Replacing the values for the force and the angle:
Fp = 33N*sin(π/5) = 33N * 0.011 = 0.363 N
Taking the distance in meters:
T = 0.2m * 0.363 N = 0.063 Nm
<h3>
Answer:</h3>
6.38 seconds
<h3>
Explanation:</h3>
We are given;
- The force exerted by the runner as 234 N
- Power used = 1100 W
- Distance as 30.0 m
We are required to determine the time taken to run the distance;
- We know that power is the rate of work done
That is;
Power = work done ÷ time
But, work done = Force × distance
Therefore;
Work done = 234 N × 30 m
= 7020 Joules
Therefore, from the formula, Power = work done ÷ time
Time = Work done ÷ power
Thus;
Time = 7020 J ÷ 1100 W
= 6.38 seconds
Hence, the time taken is 6.38 seconds
