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salantis [7]
3 years ago
7

Students in a lab are doing experiments involving the motion of objects. They pull an object across a table and use

Physics
1 answer:
Svetlanka [38]3 years ago
5 0

Answer:

Explanation:

Did you ever end up getting an answer? Or like did you find out which segment it was?

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A 2 kg, frictionless block is attached to a horizontal, ideal spring with spring constant 300 N/m. At t = 0 the spring is neithe
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Answer:

Explanation:

Given that,

Mass of block

M = 2kg

Spring constant k = 300N/m

Velocity v = 12m/s

At t = 0, the spring is neither stretched nor compressed. Then, it amplitude is zero at t=0

xo = 0

It velocity is 12m/s at t=0

Then, it initial velocity is

Vo = 12m/s

Then, amplitude is given as

A = √[xo + (Vo²/ω²)]

Where

xo is the initial amplitude =0

Vo is the initial velocity =12m/s

ω is the angular frequency and it can be determine using

ω = √(k/m)

Where

k is spring constant = 300N/m

m is the mass of object = 2kg

Then,

ω = √300/2 = √150

ω = 12.25 rad/s²

Then,

A = √[xo + (Vo²/ω²)]

A = √[0 + (12²/12.5²)]

A = √[0 + 0.96]

A = √0.96

A = 0.98m

4 0
3 years ago
A spring scale has a spring with a force constant of 250 N/m and a weighing pan with a mass of 0.075 kg. During one weighing, th
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elasticity stretches and can also return to it's normal size ..

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2 years ago
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Assoli18 [71]

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3 years ago
if a train starts from rest and attains a velocity of 100m/s in 25 seconds. calculate the acceleration produced by the train.​
stira [4]
-4 km/s2

Explanation:
0-100/25
-100/25
-4
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