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salantis [7]
3 years ago
7

Students in a lab are doing experiments involving the motion of objects. They pull an object across a table and use

Physics
1 answer:
Svetlanka [38]3 years ago
5 0

Answer:

Explanation:

Did you ever end up getting an answer? Or like did you find out which segment it was?

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The x component of vector is 8.7 units, and its y component is -6.5 units. The magnitude of is closest to
irina1246 [14]

Answer:

F = 10.86 units

Explanation:

The magnitude of a vector in terms of the magnitude of its rectangular components is given by the following formula:

F = √(Fₓ² + Fy²)

where,

F = Magnitude of the Vector = ?

Fₓ = magnitude of the x-component of vector = 8.7 units

Fy = magnitude of y component of vector = - 6.5 units

Therefore, using these values in the equation, we get:

F = √[(8.7 units)² + (- 6.5 units)²]

F = √(117.94 units²)

<u>F = 10.86 units</u>

5 0
3 years ago
What is the area of soft cartilage where bone growth occurs
VladimirAG [237]
The area of <span>the epiphyseal plate belonging from a soft cartilage is where bone growth usually begins. The production of bones inside this tissue is due to a cell division by mitosis. In addition, this process of producing bone material to replace old bone structures is called ossification.</span>
6 0
4 years ago
When neither plate is dense enough to sink into the asthenosphere, the result is a _____ plate boundary.
hjlf

Answer:  Convergent collision

6 0
3 years ago
If an object emits or reflects light,
SIZIF [17.4K]

D. It can be seen by the eye. I took this test. Hope this helped!

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3 years ago
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How much force does it take to bring a 1,050 N car from rest to a velocity of 42 m/s in 13 seconds?
frozen [14]

Answer:

F = 339.23 N

Explanation:

Weight of a car, W = 1050 N

Initial velocity, u = 0

Final velocity, v = 42 m/s

Time, t = 13 s

The weight of an object is given by :

W = mg

g is the acceleration due to gravity

m=\dfrac{W}{g}\\\\m=\dfrac{1050}{10}\\\\m=105\ kg

The force acting on car is :

F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{105\times (42-0)}{13}\\\\F=339.23\ N

So, the force acting on the car is 339.23 N.

5 0
3 years ago
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