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3 years ago

Please help me with this

Mathematics

1 answer:

ZanzabumX [31]3 years ago

8 0

Answer:

300•0.15•6

Step-by-step explanation:

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Emilio paid $287.50 in taxes for the school district this year. This year's taxes were 15% increase of last year's taxes. How mu

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2204.16, i think this is right. hope this helps <3

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3 years ago

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A system of linear equations is given by the tables<br>

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Answer:

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3 years ago

The side length of a triangle or 12.5 inch 4.4 inch and 11.72 which statement best describes the triangle formed using these

N76 [4]

Answer:

scalene

Step-by-step explanation:

12.5, 4.4, and 11.72 are all different measurements

i hope this helped

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3 years ago

A certain manufactured item is visually inspected by two different inspectors. When a defective item comes through the line, the

andreev551 [17]

The fraction of a defective item getting by both inspectors is $\frac{5}{100}$ = $\frac{1}{20}$

Step-by-step explanation:

Step 1; Assume that the probability of the first inspector missing a defective part is P(A) and the probability of the second inspector missing those that do get past the first inspector is P(B).

Step 2; It is given that P(A) = 0.1, we convert this into a fraction so that the final probability will be a fraction and not a decimal.

P(A) = 0.1 = $\frac{1}{10}$ .

It is given that the second inspector misses 5 out of 10 that get past the first inspector, so P(B) = $\frac{5}{10}$ .

Step 3; To calculate the probability of both inspectors missing a defective part, we multiply both the probabilities.

P(A and B happening) = P(A) × P(B) = $\frac{1}{10}$ × $\frac{5}{10}$ = $\frac{5}{100}$ = $\frac{1}{20}$ = 0.05%. So there is a 0.05% chance of both inspectors missing a defective part.

8 0

3 years ago

Lucia ran the 400-meter race 3 times. Her fastest time was 52.2 seconds. Her slowest time was 56.3 seconds. If Luzia’s average t

Novay_Z [31]

Answer:

53.5 sec

Step-by-step explanation:

Given

Number of times Lucia ran the race=n=3

Slowest time= x_1=56.3 sec

Fastest Time= x_2=52.2 sec

Average time=54.0 sec

Since, we know the average time and two of the three race times, we can use the average formula to calculate the third race’s time.

Let

x_3=the third race^' s time

So,

Average=(Sum of values)/(Number of values)

Average = (x_1+ x_2+ x_3)/n

Putting the values

54.0= (56.3+ 52.2+ x_3)/3

Multiplying 3 with 54.0 and adding 56.3 and 52.2

162= 56.3+52.2+ x_3

162= 108.5+ x_3

x_(3 )=162-108.5

x_(3 )=53.5 sec

6 0

3 years ago