Because Philip is conducting a survey that pertains to the weight of the cows, he needs statistics that directly relate to weight.
The cows being overweight doesn't give Philip concrete information on the weight of the cows, as it doesn't give the amount of pounds a cow weighs. Average age has nothing to do with weight, and normal body weight doesn't give concrete information on weight.
The answer is "<span>What is the weight of each cow on the farm?".</span>
2(a-b)
this is the answers
Answer:
5 containers high
Step-by-step explanation:
Given that :
Given :
Width = 20 containers
Length = 50 containers
Total containers = 5000
Hence,
Total containers = width * length * height
5000 = 20 * 50 * height
5000 = 1000 * height
Height = 5000 / 1000
Height = 5 containers
Answer: D
Step-by-step explanation:
Standard Deviation σ2 =
Σ(xi - μ)2/N
=(1 - 5.3)2 + ... + (9 - 5.3)2/10
=68.1/10
= 6.81
σ = √6.81
= 2.60959767014
B) σ2 =
Σ(xi - μ)2/N
=(3 - 61.7)2 + ... + (99 - 61.7)2/10
=58414.1/10
= 5841.41
σ = √5841.41
= 76.429117488036
C) (1 - 11.4)2 + ... + (1 - 11.4)2/10
=8758.4/10
= 875.84
σ = √875.84
= 29.59459410095
D) (79 - 79)2 + ... + (79 - 79)2/10
=0/10
= 0
σ = √0
= 0
I hope this helps, mark as Brainliest please.
