Question

What is the area in square units of triangle QRS also show work

Answer 1

Find the area of the larger rectangle. 
5 x 4 = 20  
One of the triangles is 2 x 2. Area of 2. Subtract 2 from 20.
20 - 2 = 18 
Another is 2 x 5. Area of 5. Subtract 5 from 18. 
18 - 5 = 13 
The last is 3 x 4. Area of 6. Subtract 6 from 13. 
13 - 6 = 7 
The area of the triangle QRS is A, 7. 
Hope this helps!

Answer 2

Answer:

The correct option is :  A.  7

Step-by-step explanation:

According to the below diagram, for rectangle AQBC, the length $=5$ units and the width $= 4$ units.

So, the area of the rectangle $= (length\times width)= (5\times 4)= 20$ square units.

For $\triangle AQS,$ base$(AS)= 3$ units and height$(AQ)= 4$ units.

So, area of $\triangle AQS$ $=\frac{1}{2}\times base \times height =\frac{1}{2}(3)(4)=6$ square units.

For $\triangle CSR,$ base$(CR)= 2$ units and height$(CS)= 2$ units.

So, area of $\triangle CSR$ $=\frac{1}{2}\times base \times height =\frac{1}{2}(2)(2)=2$ square units.

For $\triangle BQR,$ base$(BR)= 2$ units and height$(BQ)= 5$ units.

So, area of $\triangle BQR$ $=\frac{1}{2}\times base \times height =\frac{1}{2}(2)(5)=5$ square units.

Now, total area of $\triangle AQS$, $\triangle CSR$ and $\triangle BQR$ $=(6+2+5)= 13$ square units.

Thus, the area of $\triangle QRS$ =(Area of rectangle AQBC)-(Area of $\triangle AQS$, $\triangle CSR$ and $\triangle BQR$) $=(20-13)= 7$ square units.