Ask question

Ask question

All categories

tamaranim1 [39]

3 years ago

8

How many atoms are in 1.14 mol of sulfur trioxide

1 answer:

yawa3891 [41]3 years ago

8 0

2.75 x 10^24

Hope this helped :)

You might be interested in

Hunting lions has been banned in some parts of Africa. If this law is enforced, what can we expect to happen to the populations

k0ka [10]

The population would decrease, the more predators there are the more food needed for the species .

4 0

3 years ago

Read 2 more answers

Which element would you expect to behave the most like carbon (C)?

vesna_86 [32]

Answer:

A

Explanation:

Germanium and Carbon are in the same 14th group.

3 0

2 years ago

Read 2 more answers

Which electrons participate in chemical bonding?

OverLord2011 [107]

B.) Valence Electrons. The nucleus of the valence electrons attracts and pulls atoms together.

7 0

3 years ago

Read 2 more answers

What is a “ medium” in regards to waves ?

raketka [301]

A medium can be anything that a wave can pass through e.g the medium can be solid objects, air, water, etc.

3 0

2 years ago

Read 2 more answers

The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C

Kipish [7]

Answer: 72 grams of $O_2(g)$ are needed to completely burn 19.7 g $C_3H_8(g)$

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Putting in the values we get:

$\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles$

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$

According to stoichiometry:

1 mole of $C_3H_8$ requires 5 moles of oxygen

0.45 moles of $C_3H_8$ require= $\frac{5}{1}\times 0.45=2.25$ moles of oxygen

Mass of $O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g$

72 grams of $O_2(g)$ are needed to completely burn 19.7 g $C_3H_8(g)$

7 0

3 years ago