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Finger [1]
4 years ago
10

A student places three ice cubes in a beaker and allows them to partially melt. if she measures the temperature of the water in

the beaker, what will she most likely observe? explain your answer.
Chemistry
2 answers:
atroni [7]4 years ago
8 0

She will most likely observe that the temperature does not change during melting because the heat absorbed is used to overcome intermolecular forces rather than to increase the kinetic energy of the particles if she measures the temperature of the water in the beaker.

katen-ka-za [31]4 years ago
8 0

Temperature does not change during melting because the heat absorbed is used to overcome intermolecular forces rather than to increase the kinetic energy of the particles.

As long as both ice and water are present in the beaker, the temperature of the water will not increase.

The freezing point of water is 0°C (273 K).

The water's temperature should be 0°C (273 K).

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Given that 0.50 g Al and 5.00 g copper(II) chloride dihydrate are combined with 100.0 ml of water, determine which reactant is t
MArishka [77]
105.50 grams of total object biomass or matter mixed together which is technically chemistry.
3 0
3 years ago
How many moles of Ar gas are<br> present in a container with a<br> volume of 78.4 L at STP?
rusak2 [61]
<h3><u>Answer:</u></h3>

<u>1 mole of a gas at STP occupies 22.4 L volume </u>

<u>Now the volume is given =78.4 therefore,</u>

<u>No. of moles of gas = 78.4 ÷ 22.4 = 3.5 moles</u>

<u>I hope it helps you~</u>

7 0
2 years ago
A sample of Mo(NO3)6 has 2.22 x 10^22 nitrogen atom, how many oxygen atoms does the sample have?
goldfiish [28.3K]

There are 3.98 × 10^23 atoms of oxygen in the sample.

Given that;

1 mole of Mo(NO3)6 contains 6.02 × 10^23 atoms of Nitrogen

x moles of Mo(NO3)6 contains 2.22 x 10^22 atoms of nitrogen

x = 1 mole × 2.22 x 10^22 atoms/6.02 × 10^23 atoms

x = 0.0368 moles

The number of oxygen atoms in the sample is given by; 0.0368 × 6.02 × 10^23 × 18

Therefore, there are 3.98 × 10^23 atoms of oxygen in the sample.

Learn more: brainly.com/question/9743981

4 0
2 years ago
Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(
kkurt [141]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2Sr(s)+O_2(g)\rightarrow 2SrO(s)    \Delta H_1=-1184kJ

(2) SrO(s)+CO_2(g)\rightarrow SrCO_3(s)     \Delta H_2=-234kJ      ( × 2)

(3) CO_2(g)\rightarrow C(s)+O_2(g)     \Delta H_3=394kJ    ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ

Hence, the \Delta H^o_{rxn} for the reaction is 72 kJ.

4 0
3 years ago
HELP!!!!!!!!!! PLEASE!!! HELP!!
enyata [817]

Answer:

Ooh sweetie goodluck

Explanation:

May the gods ever be in your favor.

8 0
3 years ago
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