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3 years ago

Marshall determines that a gas has a gauge pressure of 276 kpa what's the absolute pressure of the gas

1 answer:

6 0

A gauge records the pressure over atmospheric pressure (0kpa on the gauge is actually the atmospheric pressure and a reading of 276kpa is 276kpa over atmospheric pressure). That means that means that to find absolute pressure you just add atmospheric pressure (around 1atm (101kpa)) to 286kpa to get 387kpa. I hope this helps.

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Which of these functional groups is found in all amino acids? -NH2 -OH =O -PO42-

melisa1 [442]

Answer : The correct option is, $-NH_2$

Explanation :

Amino acid : The acid that contains two functional groups that are carboxylic group, $-COOH$ and ammine group, $-NH_2$ .

When the two or more that two amino acids join together with the help of peptide bond, they produces polypeptide chain or protein.

The bond present between the two amino acid is called a peptide bond.

The peptide bond is a chemical bond that is formed between the two molecules when the nitrogen of one amino acid react with the carbon of another amino acid by releasing a water molecule. This is a dehydration synthesis or condensation reaction.

From this we conclude that, only two functional groups carboxylic group, $-COOH$ and ammine group, $-NH_2$ are present in all amino acids.

Hence, the correct option is, $-NH_2$

7 0

3 years ago

It takes 945. kJ/mol to break a nitrogen-nitrogen triple bond. Calculate the maximum wavelength of light for which a nitrogen-ni

kolezko [41]

Answer: 1.274 * 10^ -7 meter (same as 127.4 nanometers

Explanation:

It's given that the energy

required to break the N N triple bond is 945 * 10^3 joules per mole.

One mole contains 6.02 * 10^ 23 molecules, so the energy required per molecule

= 945 * 10^3 / 6.023 * 10^23, or 1.56 * 10^-18 joules.

Then we need a photon whose energy (E) is at least that amount.

The energy E of a photon is related to its frequency f by PLANCK'S EQUATUON,

E = hf,

where h is Planck's constant (6.625 * 10^-34 joule-sec)

and the wavelength w is inversely proportional to the frequency by w = c/f, where c is the speed of light, 2.998 * 10^8 meters per sec.

If h & c are both constants, their product hc is constant, so we can say E = hc/w,

or if we know E and want to find w, a little algebra gives: w = hc/E.

The product hc = 1.9875 * 10^-25 joule-meters,

so w = 1.9875 * 10^-25 / 1.56 * 10^-18, or 1.274 * 10^ -7 meter (same as 127.4 nanometers

6 0

3 years ago

Imagine a chemist is in the lab and trying to make some chemical reactions happen. In one reaction she reacts chemicals in an ex

VikaD [51]

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3 years ago

In Fig C, which pair of electrons is the lone pair?

arlik [135]

Answer:

bottom right top left fig

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2 years ago

HELP!!! TIMED! THANK YOU!

Bess [88]

Answer:

The answer is A.

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3 years ago

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