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Marina86 [1]
4 years ago
15

Which term identifies a type of organic reaction?

Chemistry
2 answers:
olga2289 [7]4 years ago
5 0

Answer:

(3) esterification

Explanation:

1) Deposition is a process in which a vapor directly condenses into a solid. It is the reverse of sublimation and therefore a process which involves a physical/phase change.

2) Distillation is a process in which a liquid mixture is separated based on the differences in their boiling points. This is a physical separation and not any form of a chemical change.

3) Esterification is an organic reaction in which a carboxylic acid is treated with an alcohol to form an ester.

4) Sublimation is again a physical/phase change process in which a solid gets converted into a gas.

lyudmila [28]4 years ago
3 0
<span>The answer is (3) esterification. Note that deposition, distillation and sublimation are not chemical changes, they are physical changes, so you can solve this question by elimination if you know that. Regarding sterification it is a well known chemical reaction that consists on the formation of esters from carboxilic acids.</span>
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viktelen [127]

Answer : The concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

Explanation :

When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is SCN^- and Fe^{3+} is excess reagent.

First we have to calculate the moles of KSCN.

\text{Moles of }KSCN=\text{Concentration of }KSCN\times \text{Volume of solution}

\text{Moles of }KSCN=0.00180M\times 0.006L=1.08\times 10^{-5}mol

Moles of KSCN = Moles of K^+ = Moles of SCN^- = 1.08\times 10^{-5}mol

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\text{Concentration of }[Fe(SCN)]^{2+}=\frac{\text{Moles of }[Fe(SCN)]^{2+}}{\text{Volume of solution}}

Total volume of solution = (6.00 + 5.00 + 14.00) = 25.00 mL = 0.025 L

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{1.08\times 10^{-5}mol}{0.025L}=4.32\times 10^{-4}M

Thus, the concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

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3 years ago
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See explanation

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