<em>so</em><em>,</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>-</em><em>8</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
Answer: 3, 5, 7
Step-by-step explanation:
There is a "trick" to determine divisibility by 3: if the sum of the digits is divisible by 3, the number is divisible by 3.
3 + 1 + 5 = 9 which is a multiple of 3, so 315 is divisible by 3.
It works for 9 also. since the sum of the digits is 9, 315 is divisible by 9.
Divisibility by 5: any number that has the units digit 5 or 0 is divisible by 5.
For 7, I just tried it 315÷7= 45
Only even numbers are divisible by 2.
If a 3-digit number is divisible by 11, the middle digit will be the sum of the first and last digits. (That is not the case for 315) But 385 is divisible by 11, also 495, 253, and many others you can try for fun.
Answer:
There will be 2 numbers of individual bags of chocolates left with Missy.
Step-by-step explanation:
Missy bought 4 bags of chocolates and there are 8 pieces of chocolates in each bag.
Therefore, there was a total (4× 8) = 32 chocolates.
Now, her kids ate 6 of the chocolates.
So, there remains (32 - 6) = 26 chocolates left.
If Missy packed the remaining chocolates into individual bags with 13 chocolates in each bag, then there will be 
numbers of individual bags of chocolates left with Missy. (Answer)
I believe it is the 9, with absolute values the number will always be positive so the absolute value of -9 is 9, which is the greatest out of all the options
