All categories

3 years ago

What is the LCM of 16 and 40 ? 24 and 40 ?

Mathematics

2 answers:

andre [41]3 years ago

5 0

Answer:

80 & 120

Step-by-step explanation:

16×5 & 40×2=80

24×5 & 40×3=120

luda_lava [24]3 years ago

4 0

Answer: 160 and 120

Step-by-step explanation:

You might be interested in

What basic trigonometric identity would you use to verify that sin^2x +cos^2x/cos x = sec x

gogolik [260]

Answer:

The basic identity used is $\bold{\sin ^{2} x+\cos ^{2} x=1}$ .

Solution:

In this problem some of the basic trigonometric identities are used to prove the given expression.

Let’s first take the LHS:

$\Rightarrow \frac{\sin ^{2} x+\cos ^{2} x}{\cos x}$

Step one:

The sum of squares of Sine and Cosine is 1 which is:

$\sin ^{2} x+\cos ^{2} x=1$

On substituting the above identity in the given expression, we get,

$\Rightarrow \frac{\sin ^{2} x+\cos ^{2} x}{\cos x}=\frac{1}{\cos x} \rightarrow(1)$

Step two:

The reciprocal of cosine is secant which is:

$\cos x=\frac{1}{\sec x}$

On substituting the above identity in equation (1), we get,

$\Rightarrow \frac{\sin ^{2} x+\cos ^{2} x}{\cos x}=\sec x$

Thus, RHS is obtained.

Using the identity $\sin ^{2} x+\cos ^{2} x=1$ , the given expression is verified.

6 0

3 years ago

Which comparison is not correct? A. -2 > -7 B. 1 -8 c. -3 > -8 D. 6 > 5

Gnom [1K]

C is the answer I think

6 0

2 years ago

Help asp, I can’t find the answers:P

zepelin [54]

Answer:

the answer will be B

Step-by-step explanation:

It does increase

8 0

3 years ago

3/4 of a class are girls. 1/3 of the girls wear bows in their hair. What fraction of the class are girls with bows in her hair

Svetradugi [14.3K]

Answer:

Step-by-step explanation:

1/3 * 3/4 = 1/4

7 0

3 years ago

This is due in 10 minutes please help me

valkas [14]

Given:

The rate of interest on three accounts are 7%, 8%, 9%.

She has twice as much money invested at 8% as she does in 7%.

She has three times as much at 9% as she has at 7%.

Total interest for the year is $150.

To find:

Amount invested on each rate.

Solution:

Suppose x be the amount invested at 7%. Then,

The amount invested at 8% = 2x

The amount invested at 9% = 3x

Total interest for the year is $150.

$x\times \dfrac{7}{100}+2x\times \dfrac{8}{100}+3x\times \dfrac{9}{100}=150$

Multiplying both sides by 100, we get

$7x+16x+27x=15000$

$50x=15000$

Dividing both sides by 50, we get

$x=\dfrac{15000}{50}$

$x=300$

So, the amount invested at 7% is $300$ .

The amount invested at 8% is

$2(300)=600$

The amount invested at 9% is

$3(300)=900$

Hence, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.

7 0

3 years ago