Multiply the following using the vertical multiplication method: 3x^2+5x+1 • x^2-2x+4

Mathematics

2 answers:

KonstantinChe [14]4 years ago

6 0

Answer:

4x^2+3x+4

Step-by-step explanation:

Let's simplify step-by-step.

3x2+5x+1x2−2x+4

=3x2+5x+x2+−2x+4

Combine Like Terms:

=3x2+5x+x2+−2x+4

=(3x2+x2)+(5x+−2x)+(4)

=4x2+3x+4

Answer:

=4x2+3x+4

guajiro [1.7K]4 years ago

4 0

Answer:

3x^4+3x+5

Step-by-step explanation:

3x^2 + 5x +1 * x^2 - 2x + 4

3x^2 * x^2 = 3x^4

5x - 2x = 3x

1+4= 5

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You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte

Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

$f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \, otherwise }} \right.$

a) We calculate the probability that you need less than 5 minutes to get up:

$P(x$

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate the probability that you will need between 8 and 13 minutes:

$P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3$

Therefore, the probability is P(8<x<13)=0.3.

d) We calculate the probability that you will be late to each of the 9:30am classes next week:

$P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6$