12 = x² - x
12 - 12 = x² - x - 12
0 = x² - x - 12
x² - x - 12 = 0
x = <u>-(-1) +/- √((-1)² - 4(1)(-12))</u>
2(1)
x = <u>1 +/- √(1 + 48)</u>
2
x = <u>1 +/- √(49)
</u> 2
x = <u>1 +/- 7</u>
2
x = 0.5 +/- 3.5
x = 0.5 + 3.5 x = 0.5 - 3.5
x = 4 x = -3
<u />
Answer:
Yes, it will reach or exceed 141 degree F
Step-by-step explanation:
Given equation that shows the temperature T in degrees Fahrenheit x minutes after the machine is put into operation is,

Suppose T = 141°F,



Since, a quadratic equation
has,
Real roots,
If Discriminant, 
Imaginary roots,
If D < 0,
Since, 
Thus, roots of -0.005x² + 0.45x + 125 are real.
Hence, the temperature can reach or exceed 141 degree F.
Answer:
3139.5 m²
Step-by-step explanation:
the formula for the volume of a sphere of radius r is V = (4/3)πr³. In this particular case, V = 2098π m³ = (4/3)πr³, and from this we can calculate the radius, r:
2098π m³
r³ = ----------------- = (3/4)(2098 = 1483/5
(4/3)π
Thus r = ∛1573.5 m³ = 11.64 m
Then the surface area is A = 4πr², which in this case is
A = 4(3.14159)(11.64 m)^2 = 1702.6 m² (which is to the nearest tenth).
X is 4 because 64 is 8 squared, so 4 would be 2 squared
Answer:
q =1
Step-by-step explanation:
q=17-18
.•. q=1
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